Question

Use triangleABC to find the value of sin B

Answer 1

The given triangle is a right triangle right angled at angle C. For angle B the adjacent side is BC ,the side opposite to angle B is AC while AB is hypotenuse. Sin of any angle is ratio of opposite and hypotenuse.

Sin$\frac{opposite}{hypotenuse}$

The opposite in the figure is 24 and hypotenuse is 25

Substituting the values of opposite and hypotenuse from figure we have:

Sin B=$\frac{24}{25}$

Answer 2

As we are given

Opposite side of the angle B=24

Hypotenuse =25

$\\ \ sin \theta=\frac{Opposite}{Hypotenuse}\\ \\ \ SinB=\frac{24}{25}$