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Colt1911 [192]
3 years ago
7

Please help I will give brainliest ;3

Chemistry
2 answers:
marin [14]3 years ago
6 0
Oxygen, carbon monoxide,Oxygen, carbon monoxide
Hatshy [7]3 years ago
3 0

Answer:

oxygen, carbondioxide

carbondioxide, oxygen

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I need three examples of objects with high density and three with low density!!
Anuta_ua [19.1K]

Answer:

For example, a suitcase jam-packed with clothes and souvenirs has a high density, while the same suitcase containing two pairs of underwear has low density. Size-wise, both suitcases look the same, but their density depends on the relationship between their mass and volume. Mass is the amount of matter in an object.

5 0
3 years ago
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Write the complete balanced equation for the reaction between aluminum metal (Al) and oxygen gas (O2). You do not need to make t
Soloha48 [4]
For the answer to the question above, asking to w<span>rite the complete balanced equation for the reaction between aluminum metal (Al) and oxygen gas (O2)and You do not need to make the subscripts smaller.
My answer would be,
</span><span>4Al(s) + 3O2(g) --->2 Al2O3(s)
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3 0
3 years ago
What is the mass of OH- in Ca(OH)2
Ne4ueva [31]
Oxygen: 16.00 g/mol
Hydrogen: 1.01 g/mol

The mass would be 17.01 g/mol
5 0
3 years ago
GIVING ALOTS OF POINTS !!! Is the following sentence true or false? Where a river flows in a straight
Neko [114]

Answer: yes true

Explanation: 1. Toward the middle of a river, water tends to flow fastest; toward the margins of the river it tends to flow slowest. 2. In a meandering river, water will tend to flow fastest along the outside bend of a meander, and slowest on the inside bend.

6 0
3 years ago
What volume will 1.27 moles of helium gas occupy at 80.00 °C and 1.00 atm?
White raven [17]

Answer:

36.8 L

Explanation:

We'll begin by converting 80 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

T(°C) = 80 °C

T(K) = 80 + 273

T(K) = 353 K

Finally, we shall determine the volume occupied by the helium gas. This can be obtained as follow:

Number of mole (n) = 1.27 moles

Temperature (T) = 353 K

Pressure (P) = 1 atm

Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) =?

PV = nRT

1 × V = 1.27 × 0.0821 × 353

V = 36.8 L

Thus, the volume occupied by the helium gas is 36.8 L

5 0
3 years ago
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