Explanation:
According to the Henderson-Hasselbalch equation, the relation between pH and
is as follows.
pH = 
where, pH = 7.4 and
= 7.21
As here, we can use the
nearest to the desired pH.
So, 7.4 = 7.21 + 
0.19 = 
= 1.55
1 mM phosphate buffer means
+
= 1 mM
Therefore, the two equations will be as follows.
= 1.55 ............. (1)
+
= 1 mM ........... (2)
Now, putting the value of
from equation (1) into equation (2) as follows.
1.55
= 1 mM
2.55
= 1 mM
= 0.392 mM
Putting the value of
in equation (1) we get the following.
0.392 mM +
= 1 mM
= (1 - 0.392) mM
= 0.608 mM
Thus, we can conclude that concentration of the acid must be 0.608 mM.
Add 450 million grams to the solution
That answer is true. bleh bleh bleh bleh
Answer: <span>Based on giveninformation, the compound is a
<u>Poly Unsaturated</u> fatty acid.
Explanation: Fatty acids are carboxylic acids with -COOH functional group and a chain of hydrocarbons.
Fatty Acids are classified as,
i) Saturated Fatty Acids: Those Fatty Acids in which there is no double bond between the carbon chain are called as saturated fatty acids.
Examples: Lauric Acid </span>CH₃(CH₂)₁₀COOH<span>
Myristic Acid </span>CH₃(CH₂)₁₂COOH<span>
Palmitic Acid </span>CH₃(CH₂)₁₄COOH
ii) Unsaturated Fatty Acids: Those Fatty Acids in which contain a single double bond (mono-unsaturated) or more than one double bond (poly-unsaturated) d between the carbon atoms in a chain are called as unsaturated fatty acids.
Examples: <span>
Linoleic acid</span>
<span>
Vaccenic acid </span><span>
Palmitoleic acid
The saturated fatty acid containing 26 carbon atoms is called as
Cerotic acid. While cerotic acid containing a double bond at position 3 and 9 has a IUPAC name
H</span>
exacosa-3,9-dienoic acid with following structure.