Answer:
4
Explanation:
A carbon atom has 4 electrons in its outermost shell (2s^2p^2). All are unpaired (none share their orbital with another electron). So all four are anxious to pair with another electron. Once it has found 4 more electrons contributed from other atom(s), it will have 4 pairs of shared electrons.
Hydrogen has one lone electron. An atom of H is downright gleeful in sharing it's electron with elements such as carbon, C. Since carbon has 4 unpaied electrons, it will combine with 4 H atoms. At that point, cabon is sharing 4 electron pairs.
NaOH is a strong base so pH will be around 13 to 12. Whatever number of moles of NaOH you have approximately the pH of NaOH will be around 14 13 or 12
Answer:
Mass = 0.00541 g
Explanation:
We will convert the larger given values in to smaller by rounding these figures.
Given data:
Mass of zinc sulfide = 43 g
Mass of oxygen = 44.2 g
Mass of zinc oxide = ?
Solution:
Chemical equation:
2ZnS + 3O₂ → 2ZnO + 3SO₂
Number of moles of ZnS:
<em>Number of moles = mass/ molar mass </em>
Number of moles = 43 g/ 97.5 g/mol
Number of moles = 0.44 mol
Number of moles of Oxygen:
<em>Number of moles = mass/ molar mass </em>
Number of moles = 44.2 g/ 32 g/mol
Number of moles = 1.4 mol
Now we will compare the moles of oxygen and zinc sulfide with zinc oxide.
ZnS : ZnO
2 : 2
0.44 : 0.44
O₂ : ZnO
3 : 2
1.4 : 2/3×1.4 =0.93
The number of moles of zinc oxide produced by ZnS are less so it will limiting reactant.
Mass of zinc oxide:
Mass = number of moles / molar mass
Mass = 0.44 mol / 81.38 g/mol
Mass = 0.00541 g
Answer: It is because tyrosine kinases and BTK have similar solubilities
Explanation:
In column chromatography, components of a mixture are seperated based on their relative solubilities in two non-mixing phases.
In essence, tyrosine kinases and BTK are present in the eluate due to their similar solubility rates that arise from the similar chemical structure both possess (otherwise it would be impossible for the inhibitor meant for Tyrosine kinase to bind and also inhibits BTK)
Thus, the similar solubilities of both groups is the reason they could elute out of the column without being adsorped.
Answer:
Positive
Explanation:
For the most effective hot pack, the temperature change should be <u>positive</u>.
<em>Hot packs are generally utilized for their heat-producing abilities. Hence, the reactions leading to the activation of hot packs are usually exothermic, that is, heat energy generating. In other words, positive or increased temperatures must be generated when hot packs are activated.</em>
This is unlike cold packs which are utilized for the cold-generating abilities. Reactions leading to their activations must be endothermic, that is, heat-absorbing.
