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IgorC [24]
3 years ago
10

What aqueous solution has the highest boiling point at standard pressure? A) 1.0 M KCl(aq) B) 1.0 M CaCl2(aq) C) 2.0 M KCl(aq) D

) 2.0 M CaCl2(aq)
Chemistry
1 answer:
Lapatulllka [165]3 years ago
5 0
The increase in the boiling point of a solvent is a colligative property.


That means that the increase in the boling point will be related to the number of particles (molecules or ions) present in the solution.


The higher the number of particles (molecules or ions) the higher the increase in the boiling point.


All the aqueous solutions presented are electrolytes, i.e. the solutes are ionic compounds.


Then, you have to compare the number of ions that you have in each solution.


A) 1.0 M KCl ---> 1.0 M K+     +      1.0 MCl-    = 2 moles of particles / liter


B) 1.0 M CaCl2 --> 1.0M Ca(2+)      +      1.0M * 2 Cl (-)    = 3 moles of particle / liter


C) 2.0M KCl ---> 2.0 M K+      +      2.0 M Cl-  = 4 moles of particle / liter


D) 2.0 M CaCl2 ----> 2.0 M Ca (2+)      + 2.0M * 2 Cl (-)  = 6 moles of particle / liter.


Then, the solution 2.0M CaCl2(aq) has the highest increase in the boiling point.


Answer: option D) 2.0 M Ca Cl2(aq)
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1 points)<br> You have 300 grams of Al2(CO3)3. How many moles are produced?
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0.5133805136 moles.

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The CO2 that builds up in the air of a submerged submarine can be removed by reacting it with sodium peroxide. 2 Na2O2 (s) + 2 C
grandymaker [24]

Answer: The sodium peroxide needed per sailor in a 24 hr period is 674 grams.

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 1.02 atm

V = Volume of gas = 150.0 ml = 0.15 L

n = number of moles  of carbon dioxide = ?

R = gas constant =0.0821Latm/Kmol

T =temperature =20^0C=(20+273)K=293K

n=\frac{PV}{RT}

n=\frac{1.02atm\times 0.15L}{0.0821 L atm/K mol\times 293K}=0.006moles

2Na_2O_2(s)+2CO_2(g)\rightarrow 2Na_2CO_3(s)+O_2(g)

According to stoichiometry:

2 moles of carbon dioxide require = 2 moles of sodium peroxide

Thus 0.006 moles carbon dioxide require= \frac{2}{2}\times 0.006=0.006 moles of  sodium peroxide

Mass of  sodium peroxide needed for 24 hour=moles\times {\text {Molar mass}}=0.006mol\times 78g/mol\times 24\times 60=674g

Thus sodium peroxide needed per sailor in a 24 hr period is 674 grams.

4 0
2 years ago
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