Answer:
e. 81.0%
Explanation:
Morphine has Molar mass = 285.34 g/mol
Also, number of males of Morphine = Number of moles of HCl
(At equivalence point )
Now, number of moles of HCl = Molarity × volume
=0.01 mol × 2.84×10^(-3) L
= 2.84×10^(-5) mol
therefore number of moles of morphine= 2.85×10^(-5)
Mass of Morphine= No. of moles × molar mass
= 2.84×10^(-5)×285.34 g/mol
= 0.0081 g
= 8.1 mg
therefore
percentage of morphine = mass of morphine/ mass of powder×100%
= 8.1/10×100% = 81.0%
hence option e is correct.
Answer:
conc. fuming, 1 mol H2SO4
Dilute NaOH
Br2
Dilute H2SO4
Explanation:
The synthesis of ortho-bromophenol follows the reaction sequence shown in the image attached.
First of all, the phenol is sulphonated using concentrated sulphuric acid at 100°C. Carrying out the reaction at 100°C ensures that the para-isomer predominates. Lower temperatures favour the formation of the ortho isomer. Dilute sodium hydroxide is added before the addition of bromine.
Bromine molecule is then added. The incoming electrophile now attaches to the ortho position. Dilute acid is added at 100°C to remove the -SO3H thereby obtaining the Ortho-bromophenol
In order to answer this question, we are going to look at the molar ratio between H2O and H2, we can see that by analyzing the numbers in front of the compounds, and we can see that the molar ratio is 2:2, this means that for every 2 moles of water decomposing, we will end up with 2 moles of H2 being produced, therefore the same amount of moles for H2O will be the same amount of moles of H2, which means that if we have 100 moles of H2O being decomposed, we will also have 100 moles of H2 being produced.
The increase in the average kinetic energy of the molecules needs the increase of temperature. The relation of ℃ and K is n ℃ = m K -273. So if we change all the K unit to ℃ unit, we can get the answer is (1).