Explanation:
It is known that relation between Gibb's free energy and equilibrium or reaction quotient is as follows.
..... (1)
At equilibrium, = 0. Also, Q = K this means that reaction is at equilibrium.
Therefore, formula in equation (1) will become as follows.
....... (2)
It is known that for a sparingly soluble salt, K =
Thus, equation (2) will become as follows.
....... (3)
So, when value of increases then there will be decrease in the value of according to equation (3).
Hence, we can conclude that the calculated value of would be too big.