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melomori [17]
3 years ago
12

23) Assuming STP, how many moles are in 30 L SO2?

Chemistry
1 answer:
xenn [34]3 years ago
3 0

Answer:

1.34 moles SO₂(g)

Explanation:

At STP 1 mole of any gas occupies 22.4 Liters. So, for 30 Liters ...

moles SO₂(g) = 30L/22.4L·mol⁻¹ = 1.34 moles SO₂(g)

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A balloon that had a volume of 3.50 L at 25.0°C is placed in a hot room at 40.0°C. If the pressure remains constant at 1.00 atm,
belka [17]

To solve this we assume that the gas inside the balloon is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant pressure and number of moles of the gas the ratio T/V is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

T1 / V1 = T2 / V2

V2 = T2 x V1 / T1

V2 = 313.15 x 3.50 / 298.15

<span>V2 = 3.68 L</span>

6 0
3 years ago
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How many grams of nickel are in 1.57 moles of nickel
Crank
Question: <span>How many grams of Nickel are in 1.57 moles of nickel

There are 58.6934 grams of Nickel in 1 mole. 

There are 92.1486 grams of Nickel in 1.57 moles.

Nickle is the most common ore to find on Earth. The atomic number of Nickle is 28 and the symbol for Nickle is Ni. The color is silvery-white with a tinge of gold.

Final Answer:
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There are 92.1486 grams of Nickel in 1.57 moles.
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3 years ago
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Which of the following statements is incorrect? Group of answer choices The product of wavelength and frequency of electromagnet
morpeh [17]

Answer: Option (b) is the correct.

Explanation:

It is known that energy is directly proportional to frequency.

Mathematically,              E \propto \nu

or,                           E = h \times \nu ............ (1)

where,     E = energy

                h = Plank's constant

              \nu = frequency

This relation shows that higher is the energy then more will be the frequency of electrmagnetic radiation.

Also,     \nu = \frac{c}{\lambda} ......... (2)

where,          c = speed of light

                 \lambda = wavelength

Therefore, substituting value of \nu from equation (2) into equation (1) as follows.

                 E = h \times \nu

                 E = h \times \frac{c}{\lambda}

This relation shows that higher is the energy then lower will be the wavelength.

Thus, we can conclude that as the energy of a photon increases, its frequency decreases, is incorrect statement.

3 0
3 years ago
The breaking buffer that we use this week contains 10mM Tris, pH 8.0, 150mM NaCl. The elution buffer is breaking buffer that als
olasank [31]

Answer:

A breakdown of the breaking buffer was first listed with its respective component and their corresponding value; then a table was made for the stock concentrations in which the volume that is being added was determined by using the formula M_1*V_1 = M_2*V_2. It was the addition of these volumes altogether that make up the 0.25 L (i.e 250 mL)  with water

Explanation:

Given data includes:

Tris= 10mM

pH = 8.0

NaCl = 150 mM

Imidazole = 300 mM

In order to make 0.25 L solution buffer ; i.e (250 mL); we have the following component.

Stock Concentration             Volume to be             Final Concentration

                                               added            

1 M Tris                                     2.5 mL                         10 mM

5 M NaCl                                  7.5 mL                        150 mM

1 M Imidazole                           75 mL                         300 mM    

M_1*V_1 = M_2*V_2. is the formula that is used to determine the corresponding volume that is added for each stock concentration

The stock concentration of Tris ( 1 M ) is as follows:

M_1*V_1 = M_2*V_2.

1*V_1= 0.01 M *250mL\\V_1 = 2.5mL

The stock concentration of NaCl (5 M ) is as follows:

M_1*V_1 = M_2*V_2.

1*V_1= 0.15 M *250mL\\V_1 = 7.5mL

The stock concentration of Imidazole (1 M ) is as follows:

M_1*V_1 = M_2*V_2.

1*V_1= 0.03 M *250mL\\V_1 = 75mL

Hence, it is the addition of all the volumes altogether that make up 0.25L (i.e 250 mL) with water.

5 0
3 years ago
you just got home from a run on a hot Atlanta afternoon. you grab a 1.00-liter bottle of water and drink three-quarters of it in
nikitadnepr [17]

Answer:

41.67 mol

Explanation:

1 Litre of water = 1000g

Mole = mass / molar mass

Mass of 1 L of water = 1000 g

Molar mass of water (H2O) :

(H = 1, O = 16)

H2O = (1 * 2) + 16 = (2 + 16) = 18g/mol

Amount of water consumed = (3/4) of 1 litre

= (3/4) * 1000g

= 750g

Therefore mass of water consumed = 750g

Mole = 750g / 18g/mol

Mole of water consumed = 41.6666

= 41.67 mol

3 0
3 years ago
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