To solve this we assume
that the gas inside the balloon is an ideal gas. Then, we can use the ideal gas
equation which is expressed as PV = nRT. At a constant pressure and number of
moles of the gas the ratio T/V is equal to some constant. At another set of
condition of temperature, the constant is still the same. Calculations are as
follows:
T1 / V1 = T2 / V2
V2 = T2 x V1 / T1
V2 = 313.15 x 3.50 / 298.15
<span>V2 = 3.68 L</span>
Question: <span>How many grams of Nickel are in 1.57 moles of nickel
There are 58.6934 grams of Nickel in 1 mole.
There are 92.1486 grams of Nickel in 1.57 moles.
Nickle is the most common ore to find on Earth. The atomic number of Nickle is 28 and the symbol for Nickle is Ni. The color is silvery-white with a tinge of gold.
Final Answer:
</span>
There are 92.1486 grams of Nickel in 1.57 moles.
Answer: Option (b) is the correct.
Explanation:
It is known that energy is directly proportional to frequency.
Mathematically, 
or, E =
............ (1)
where, E = energy
h = Plank's constant
= frequency
This relation shows that higher is the energy then more will be the frequency of electrmagnetic radiation.
Also,
......... (2)
where, c = speed of light
= wavelength
Therefore, substituting value of
from equation (2) into equation (1) as follows.
E =
E =
This relation shows that higher is the energy then lower will be the wavelength.
Thus, we can conclude that as the energy of a photon increases, its frequency decreases, is incorrect statement.
Answer:
A breakdown of the breaking buffer was first listed with its respective component and their corresponding value; then a table was made for the stock concentrations in which the volume that is being added was determined by using the formula
. It was the addition of these volumes altogether that make up the 0.25 L (i.e 250 mL) with water
Explanation:
Given data includes:
Tris= 10mM
pH = 8.0
NaCl = 150 mM
Imidazole = 300 mM
In order to make 0.25 L solution buffer ; i.e (250 mL); we have the following component.
Stock Concentration Volume to be Final Concentration
added
1 M Tris 2.5 mL 10 mM
5 M NaCl 7.5 mL 150 mM
1 M Imidazole 75 mL 300 mM
. is the formula that is used to determine the corresponding volume that is added for each stock concentration
The stock concentration of Tris ( 1 M ) is as follows:
.

The stock concentration of NaCl (5 M ) is as follows:
.

The stock concentration of Imidazole (1 M ) is as follows:
.

Hence, it is the addition of all the volumes altogether that make up 0.25L (i.e 250 mL) with water.
Answer:
41.67 mol
Explanation:
1 Litre of water = 1000g
Mole = mass / molar mass
Mass of 1 L of water = 1000 g
Molar mass of water (H2O) :
(H = 1, O = 16)
H2O = (1 * 2) + 16 = (2 + 16) = 18g/mol
Amount of water consumed = (3/4) of 1 litre
= (3/4) * 1000g
= 750g
Therefore mass of water consumed = 750g
Mole = 750g / 18g/mol
Mole of water consumed = 41.6666
= 41.67 mol