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3 years ago

A fourth degree polynomial with real coefficients can have -4, 8i,+4i, and as its zeros. True or false? Justify your answer.

1 answer:

4 0

You didn't give the fourth zero, but the answer is still false. If you have a root or an imaginary number as a zero, then its conjugate is also a zero. So if 8i is a zero, then -8i must also be a zero, and if 4i is a zero, then -4i must be a zero, with those zeros and -4, the number of zeroes exceeds the number of zeroes that a fourth degree polynomial can have.

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What is the result when the number 86 is decreased by 9%?

Vikki [24]

78.26

Hope this helps!!!

6 0

3 years ago

Suppose p(a) = 0.40 and p(a 

sveticcg [70]

Between the probability of union and intersection, it's not clear what you're supposed to compute. (I would guess it's the probability of union.) But we do know that

$P(A\cup B)+P(A\cap B)=P(A)+P(B)$

For parts (a) and (b), you're given everything you need to determine $P(B)$ .

For part (c), if $A$ and $B$ are mutually exclusive, then $P(A\cap B)=0$ , so $P(A\cup B)=P(A)+P(B)$ . If the given probability is $P(A\cup B)=0.55$ , then you can find $P(B)=0.15$ . But if this given probability is for the intersection, finding $P(B)$ is impossible.

For part (d), if $A$ and $B$ are independent, then $P(A\cap B)=P(A)\cdot P(B)$ .

8 0

3 years ago

Alexandra and Austin applied to the same university. They looked up the average SAT score of students admitted to that universit

Deffense [45]

Answer:

x= (y+40)-(y-330)

Step-by-step explanation:

According to the information provided, the difference in their scores would be the result of subtracting Austin's SAT score from Alexandra's SAT score.

Then, as Alexandra's SAT score was 40 points above the average score this means that you have to add 40 to the average score to get her result. Also, as Austin's SAT score was 330 points below the average score, this means that you have to subtract 330 from the average score. With this you can write the expression:

x= difference in their scores

y= average score

x= (y+40)-(y-330)

7 0

3 years ago

How do I solve these equations

Sever21 [200]

You need to know the properties of each function.
Tan is opposite (y) over adjacent (x). Sin>0 means that sin is positive, therefore, it is located on either quadrant 1 or 2. Tan=4/3 so it is located in quadrant 1.
The side of the triangle must be Adjacent=3 opposite=4 and hypotenuse=5
Now, you are asked to find the half angle of Cos which is
$\sqrt{\frac{1+cos}{2} }$
By following the formula, cos=3/5 then:
$\sqrt{ \frac{1- \frac{3}{5} }{2} }$ Multiply everything (inside the square $\sqrt{ \frac{5+3}{10} }$ root) by 5
$\frac{2 \sqrt{2} }{ \sqrt{10} }$
$\frac{2 \sqrt{20} }{10}$ Then just simplify
$\frac{ \sqrt{20} }{5}$ The answer is Square root of 20 over 5

3 0

3 years ago

What is equivalent to 1/2+1/6

m_a_m_a [10]

Answer:

4/6 or 2/3.

Step-by-step explanation:

You need to multiply 1/2 by 3/3 so you can can the denominater having a 6.

3 0

2 years ago