A fourth degree polynomial with real coefficients can have -4, 8i,+4i, and as its zeros. True or false? Justify your answer.

1 answer:

4 0

You didn't give the fourth zero, but the answer is still false. If you have a root or an imaginary number as a zero, then its conjugate is also a zero. So if 8i is a zero, then -8i must also be a zero, and if 4i is a zero, then -4i must be a zero, with those zeros and -4, the number of zeroes exceeds the number of zeroes that a fourth degree polynomial can have.

You might be interested in

Easy points for those who are good at math!

zalisa [80]

Answer:

The answer is A) y = -7x - 7.

Step-by-step explanation:

First, you need to subtract '7x' from both sides, and once that is done, the equation is in slope-intercept form because it is in y=mx+b form. I'll attach a photo below that explains my process! :) And another possible answer would be y = 7x + 7, but that is not an option listed above.

Hope this helps! Feel free to give me Brainliest if you feel this helped. Have a good day, and good luck on your assignment. :)