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Marina CMI [18]
3 years ago
14

At the start of his race, an 81-kg runner pushes against the starting block, exerting an average force of 1600 N . The force tha

t the block exerts on his foot points 20∘ above the horizontal. Determine the horizontal speed of the runner after the force is exerted for 0.28 s.
Physics
1 answer:
balandron [24]3 years ago
3 0
The force in the horizontal direction is given by 1600cos(20)=1503.5N
Given the mass of m=81kg, we can use F=ma to get acceleration
F/m=a
a=1503.5/81=18.56m/s²
The velocity is given by the integral of the acceleration, V=18.56t m/s
since t=0.28s we get
v=18.56(0.28)=5.197m/s
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sashaice [31]

Answer:

D

Explanation:

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2 years ago
What pressure, in millimeters of mercury (mm Hg), is equivalent to 2.13 atmospheres
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The "Standard Atmosphere" is 760 mm Hg . 2.13 times that pressure is (2.13 x 760) = 1,618.8 mm Hg.
6 0
3 years ago
The density of aluminum is 2.7 g/cm3. A metal sample has a mass of 52.0 grams and a volume of 17.1 cubic centimeters. Could the
Fudgin [204]
 Answer:  
__________________________________________________
            No;  the sample could not be aluminum;
since the density of aluminum, " 2.7 g/cm³ " , is NOT close enough to the density of the sample, " 3.04 g/cm³ " .
________________________________________________
Explanation:
________________________________________________
Density is expressed as "mass per unit volume" ;

  in which:
     "mass, "m", is expressed in units of "g" (grams);  and:
     "Volume, "V", is expressed in units of "cm³ " (such as in this problem); or                                                   in units of "mL" ;
__________________________________________________
            {Note the exact conversion:  " 1 cm³ = 1 mL " .}. 
__________________________________________________
  The formula for density:  D = m/V ;

Given:  The density of aluminum is:  2.7 g/cm³.

Given:  A sample has a mass of 52.0 g ; and Volume of 17.1 cm³ ; could it be aluminum?
_________________________________________________________
Let us divide the mass of the sample by the volume of the sample;
by using the formula:
___________________________________________
            D = m / V ;  

     and see if the value is at, or very close to "2.7 g/cm³ ".  

If it is, then it could be aluminum.
____________________________________________________
The density for the sample:

  D = (52.0 / 17.1)   g/cm³ = 3.0409356725146199 g/cm³ ;
                                              →round to "3 significant figures" ;
                                          = 3.04 g/cm³ .
_______________________________________________
No; the sample could not be aluminum; since the density of aluminum, 
   "2.7 g/cm³ "   is NOT close enough to the density of the sample,
                        "3.04 g/cm³ " .
____________________________________________________
5 0
3 years ago
a 5.0-ft woman wishes to see a full length image of herself. what is the minimum length mirror required?​
nadezda [96]

Answer:

2.5 ft

Explanation:

minimum size of the mirror should be one half the person's height.

For this woman of 5 feet height, she would therefore need a mirror of length 2.5 feet

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4 0
1 year ago
Please help. Having a hard time figuring out
Goryan [66]
Yeah that’s is correct
5 0
3 years ago
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