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Marina CMI [18]
3 years ago
14

At the start of his race, an 81-kg runner pushes against the starting block, exerting an average force of 1600 N . The force tha

t the block exerts on his foot points 20∘ above the horizontal. Determine the horizontal speed of the runner after the force is exerted for 0.28 s.
Physics
1 answer:
balandron [24]3 years ago
3 0
The force in the horizontal direction is given by 1600cos(20)=1503.5N
Given the mass of m=81kg, we can use F=ma to get acceleration
F/m=a
a=1503.5/81=18.56m/s²
The velocity is given by the integral of the acceleration, V=18.56t m/s
since t=0.28s we get
v=18.56(0.28)=5.197m/s
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<u>Explanation:</u>

Power may be defined as the rate of doing work (or) work done per unit time. One unit of energy is used to do the one unit of work.

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Given, Force = 80 N,    height = 5 m , final velocity = 4 m/s

To calculate the power, we must know the time taken.

To find the time, use the distance and speed formula which is given by

                              Time = Distance / speed

Here distance = 5 m and speed = 4 m/s

                              Time = 5 / 4 = 1.25 s.

Now,          Power = work done / time

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                  Power = 320 W.

The standard unit of power is watt (W) which is joule per second.

                                                               

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lara31 [8.8K]

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The meter-out circuit can be very accurate, but are not efficient. The meter-out circuit can control overrunning as well as opposing loads while the other one method must be used with opposing loads only. The choice of flown control valve method and the location of the flow control in the circuit are dependent on the type of application being controlled.

<h3>What is a Circuit ?</h3>

In electronics, a circuit is a complete circular conduit through which electricity flows. A simple circuit consists of conductors, a load, and a current source. The term "circuit" broadly refers to any continuous path via which electricity, data, or a signal might flow.

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Hence, flow control circuit design that can best control an overrunning load is the opposing circuit

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Answer:

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