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barxatty [35]
3 years ago
5

If san andreas fault slips 2.5 cm each year how far would it separate in 100 years

Physics
1 answer:
nadya68 [22]3 years ago
7 0

Answer:

250cm or 2.5m

Explanation:

using direct variation

the length is = l

the time (year) = t

let k be the constant

so he have:

l=kt

2.5=k× 1

k= 2.5

Now in the next statement the 100 is given but not the length so

l=kt

~ l=k× 100 years

But k = 2.5

so :

l= 2.5×100

l= 250 cm

Hence it will be 250cm or 2.5m at which they will get separated

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Answer:

\Delta U = 1640 J

Explanation:

As we know by first law of thermodynamics that for ideal gas system we have

Heat given = change in internal energy + Work done

so here we will have

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also we know that work done by the system is given as

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6 0
3 years ago
An ac generator with Em = 223 V and operating at 399 Hz causes oscillations in a series RLC circuit having R = 222 Ω, L = 147 mH
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Answer:

Xc= 17.267 Ω,   Z= 415.5 Ω,   I= 0.537 A

Explanation:

Em = 223 V

f= 300 Hz, R = 222 Ω, L = 147 mH,  C = 23.1 μF

a)

Capacitive reactance = Xc=?

Xc= \frac{1}{2\pi fC}

Xc=1/2pi *399*23.1*10^-6

Xc= 17.267 Ω

b).

Z=\sqrt{ R^2 + (Xl - Xc)^2}

Xl= 2π * f * L  

Xl= 2π * 399 * 147 * 10^{-3}

Xl= 368.5 Ω

Z=\sqrt{ R^2 + (Xl - Xc)^2} = \sqrt{222^2 + (368.5 - 17.267)^2}

Z= 415.5 Ω  

c).

Current:

I= V / Z= Em / Z

I= 223/415.5

I= 0.537 A

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