Answer:
T₂ = 123.9 N, θ = 66.2º
Explanation:
To solve this exercise we use the law of equilibrium, since the diaphragm does not appear, let's use the adjoint to see the forces in the system.
The tension T1 = 100 N, we create a reference frame centered on the pole
X axis
T₁ₓ - 
= 0
T_{2x}= T₁ₓ
Y axis y
T_{1y} + T_{2y} - 200N = 0
T_{2y} = 200 -T_{1y}
let's use trigonometry to find the component of the stresses
sin 60 = T_{1y} / T₁
cos 60 = t₁ₓ / T₁
T_{1y} = T₁ sin 60
T1x = T₁ cos 60
T_{1y}y = 100 sin 60 = 86.6 N
T₁ₓ = 100 cos 60 = 50 N
for voltage 2 it is done in the same way
T_{2y} = T₂ sin θ
T₂ₓ = T₂ cos θ
we substitute
T₂ sin θ= 200 - 86.6 = 113.4
T₂ cos θ = 50 (1)
to solve the system we divide the two equations
tan θ = 113.4 / 50
θ = tan⁻¹ 2,268
θ = 66.2º
we caption in equation 1
T₂ cos 66.2 = 50
T₂ = 50 / cos 66.2
T₂ = 123.9 N
Initial momentum of the Play-doh: 0.0600 x 2.60 = 0.156 kg/m/s
Total mass of the block and play-doh: 0.38 + 0.0600 = 0.44 kg.
Final momentum is mass x velocity = 0.44v
V = Initial momentum / mass
V = 0.156 / 0.44 = 0.3545 m/s
Work done by spring is equal to the Kinetic enrgy.
Work Done by spring = 1/2 *28.0 * distance^2 = 14 * d^2
KE = 1/2 * 0.44* 0.3545^2
set to equal each other:
14 * d^2 = 0.22 *0.12567
Solve for d:
d = √(0.22*0.12567)/14
d = 0.44 meters = 4.4cm
Answer:
At the center of the object
At the end of the object farthest away from the ground
At the center of gravity of the object
At end of the object closest to the ground
Explanation:
Answer:
the sphere
Explanation:
From the given information,
A free flow body diagrammatic expression for the small uniform disk and a small uniform sphere which are released simultaneously at the top of a high inclined plane can be seen in the image attached below.
From the diagram;
The Normal force mgsinθ - Friction force F = mass m × acceleration a
Meanwhile; the frictional force
where
in a rolling motion
Then;
∴
The Normal force mgsinθ - F = m × a can be re-written as:
making a the subject of the formula, we have:
Similarly;
I = mk² in which k is the radius of gyration
∴
replacing I = mk² into the above equation , we have:
where;
the uniform disk 
the uniform sphere 
∴
We can now see that the uniform sphere is greater than the disk as such the sphere will reach the bottom first.
Answer:
The product of mass times velocity for both objects is the same.
Explanation:
They both have the same velocity. False
They both have the same mass. False: Because two objects of different masses can have the same momentum. The least massive of the two objects will have the greatest kinetic energy.
The product of mass times velocity for both objects is the same. True: Same momentum means that the large mass must have a small velocity; therefore, their product is equal to the small mass times a large velocity.
Mass and velocity is the same for both. False: Based on what was stated for the second option.
