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barxatty [35]
3 years ago
5

If san andreas fault slips 2.5 cm each year how far would it separate in 100 years

Physics
1 answer:
nadya68 [22]3 years ago
7 0

Answer:

250cm or 2.5m

Explanation:

using direct variation

the length is = l

the time (year) = t

let k be the constant

so he have:

l=kt

2.5=k× 1

k= 2.5

Now in the next statement the 100 is given but not the length so

l=kt

~ l=k× 100 years

But k = 2.5

so :

l= 2.5×100

l= 250 cm

Hence it will be 250cm or 2.5m at which they will get separated

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6. An article, which costs Rs. 850 is sold at a profit of 6%.
geniusboy [140]

Answer:

b) Rs.901  is the selling price

Explanation:

selling price = cost price+profit percentage/100 x cost price

cost price = 850

profit percentage = 6%

selling price = 850+6/100 x 850 = 901

soln 2

                              if 100 % = 850

therefore what about 106% = ?

106 x 805/100 = 901

ans = 901

if you need any clarification or more explanation pls do mention on the comment section.i would like to help more

Hope this helps and if it does mark as branliest answer thx

5 0
2 years ago
Which of the following most directly shows how physics affects society?
Nataliya [291]

the answer is definitely A.

5 0
2 years ago
In the 1920s what did Edmund hubble notice about the galaxies
zlopas [31]
Hubble noticed that the galaxies were moving away from us, which meant the universe was expanding.

This is why constellations change over time. In some years, the Big Dipper won't actually look like a dipper anymore.
5 0
2 years ago
If two charged objects each have 2.5 C of charge on them and are located 100 m apart, how strong is the electrostatic force betw
LiRa [457]

Answer:

5.619×10⁶ N

Explanation:

Applying,

F = kqq'/r²................... Equation 1

Where F = electrostatic force between the charges, k = coulomb's constant, q = first charge, q' = second charge, r = distance btween the charges

From the questiion,

Given: q = 2.5 C, q' = 2.5 C, r = 100 m

Constant: 8.99×10⁹ Nm²/C²

Substitute these values into equation 1

F = (2.5×2.5×8.99×10⁹)/100²

F = 56.19×10⁵

F = 5.619×10⁶ N

4 0
2 years ago
What are the conditions required for a rigid body to be in translational equilibrium?
kolezko [41]

Answer:

Explanation:

The condition for translation equilibrium is that is that the net force acting on the body must be zero.

The sum all the external forces acting on the body in horizontal as well as vertical direction must be zero.

∑Fₓ=0  and ∑Fy=0

now if the above two condition are satisfied the rigid body is said to be in  translational equilibrium.

God bless... hope this help to clear your doubt.

5 0
3 years ago
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