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MA_775_DIABLO [31]
3 years ago
6

Which of the following does not apply to water molecules?

Chemistry
1 answer:
serg [7]3 years ago
4 0

Answer:

It is the last one.

Explanation:

Water molecules are polar, they have cohesive properties, and water is less dense when it is solid than when it is a liquid, that is why ice floats in liquid water. However, water is a very good solvent, it can dissolve many solids, including sugar, salt, and other hydrophilic substances.

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Show dipole dipole force of water and ethyll alcohol.​
Alexeev081 [22]

Answer:

Water: H2O --> [H+] + [OH-]

Ethyl alcohol: C2H5OH --> [C2H5O-] + [H+]

Explanation:

Dipole-dipole force is observed when an ionic compound ionizes (forms ions), revealing its slightly positive ion and slightly negatively ion.

The chemical formula of Water is H2O.

H2O --> [H+] + [OH-]

The chemical formula of ethyl alcohol is C2H5OH.

C2H5OH --> [C2H5O-] + [H+]

Note the positive and negative parts of both water and ethyl alcohol as expressed in the equations above.

6 0
3 years ago
In a chemical reaction, ____ interact to form ____. select one:
QveST [7]
A. Reactants, products

In a chemical reaction, reactants interact to form products
7 0
3 years ago
How many moles would be in 85.OmL of 0.750M KOH?
Harlamova29_29 [7]

Answer: There are 0.0637 moles present in 85.0 mL of 0.750 M KOH.

Explanation:

Given: Volume = 85.0 mL (1 mL = 0.001 L) = 0.085 L

Molarity = 0.750 M

It is known that molarity is the number of moles of solute present in liter of a solution.

Therefore, moles present in given solution are calculated as follows.

Molarity = \frac{moles}{Volume (in L)}\\0.750 M = \frac{moles}{0.085 L}\\moles = 0.0637 mol

Thus, we can conclude that there are 0.0637 moles present in 85.0 mL of 0.750 M KOH.

7 0
3 years ago
a swimming pool is 50 meters long. each day a swimmer swam total of 75 lengths of the pool for practice. how many kilometers did
Brilliant_brown [7]
50x75=3750 -- metres per day
3750x15=56250 -- metres in 15 days

Divide by 1000 to convert to km
56.250km
<u>56.25km</u>
8 0
3 years ago
How many moles of a gas sample are in a 10.0 L container at 298 K and 203 kPa? (Use the ideal gas law PV = nRT with R = 8.31 L-k
weeeeeb [17]
Ideal gas law: PV = nRT

P-pressure
V-volume
n-number of moles(m/M)
R-constant
T- temperature

State given info:
V=10L
T=298k
P=203kPa
R=8.31(only for kPa, for pressure at atm use 0.08206)

Sub in:
(203kPa)(10L)=n(8.31)(298)

Rearrange:
n= (203)(10) / (8.31)(298)
n = 0.819745mol in gas sample
8 0
3 years ago
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