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Naddik [55]
3 years ago
7

Convert 6.21 km to m

Chemistry
1 answer:
nydimaria [60]3 years ago
4 0
3.86 MILES if thats what your looking foe
You might be interested in
In a redox reaction, which particles are lost and gained in equal numbers
Anna35 [415]
In a redox reaction electrons are lost and gained in equal numbers. The species that is oxidized gives electrons to the species that is reduced. I hope this helps. Let me know if anything is unclear.
5 0
4 years ago
Methyl red is a common acid-base indicator. it has a ka equal to 6.3 × 10–6. its un-ionized form is red and its anionic form is
Maksim231197 [3]
Hello!

The pKa of an indicator tells us the pH where it changes color. The pKa of Methyl red is 

pKa=-log(Ka)=-log( 6,3*10^{-6} )=5,20

So, at a pH=7,8, Methyl Red would be at a pH over its pKa, so it would be in its basic form. The Basic Form of Methyl Red is Yellow, so the solution would be Yellow.

Have a nice day!
7 0
3 years ago
In an electrically neutral atom,
Soloha48 [4]

Answer:

the number of protons equals the number of

electrons

Explanation:

Because these particles have the same but opposite charges, equal numbers cancel out, producing a neutral atom.

3 0
3 years ago
[2] in which substance are molecules rigidly arranged?
Ulleksa [173]
It would have to be c3
6 0
4 years ago
Gaseous methane (CH4) reacts with gaseous oxygen gas (O2) to produce gaseous carbon dioxide (CO2) and gaseous water (H2O). If 28
elena-14-01-66 [18.8K]

Answer:

68.1% is percent yield of the reaction

Explanation:

The reaction of methane with oxygen is:

CH₄ + 2O₂ → CO₂ + 2H₂O

<em>Where 2 moles of oxygen react per mole of CH₄</em>

<em />

Percent yield is:

Actual yield (28.2g CO₂) / Theoretical yield * 100

To solve this question we need to find theoretical yield finding limiting reactant :

<em>Moles CH₄:</em>

15.1g CH₄ * (1mol / 16.04g) = 0.9414 moles

<em>Moles O₂:</em>

81.2g * (1mol / 32g) = 2.54 moles

For a complete reaction of 0.9414 moles of CH₄ are needed:

0.9414 moles CH₄ * (2 mol O₂ / 1mol CH₄) = 1.88 moles of O₂. As there are 2.54 moles, O₂ is in excess and <em>CH₄ is limiting reactant</em>

In theoretical yield, the moles of methane added = Moles of CO₂ produced. That is 0.9414 moles CO₂. In grams = Theoretical yield:

0.9414 moles CO₂ * (44.01g / mol) = 41.43g CO₂

Percent yield: 28.2g CO₂ / 41.43g CO₂ * 100=

<h3>68.1% is percent yield of the reaction</h3>
6 0
3 years ago
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