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Andrei [34K]
3 years ago
8

Which of the following best describes a single-replacement reaction?

Chemistry
1 answer:
miss Akunina [59]3 years ago
4 0

Answer:

One element takes the place of another in a compound

Explanation:

a p e x - just did the test

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HELP 20 POINTS <br>A photon has a wavelength of 366 nm. What is the frequency of this photon?​
den301095 [7]

Answer:

9.  8.2x10¹⁴ Hz

Explanation:

Wavelength λ = 366 nm

Formula: Frequency = C / λ

To find the wavelength in m,

1 nm = 1.0x10⁻⁹ m

So, 366 nm = ?

= 3.66x10⁻⁷ m

Frequency = 3.0x10⁸m.s-1 / 3.66x10⁻⁷ m

                  = 8.2x10¹⁴ s-1

8 0
3 years ago
The conversation of cyclopropane to propene in the gas phase is a first order reaction with a rate constant of 6.7x10-⁴s-¹. a) i
Rus_ich [418]

Answer: a)  The concentration after 8.8min is 0.17 M

b) Time taken for the concentration of cyclopropane to decrease from 0.25M to 0.15M is 687 seconds.

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

t = age of sample

a = let initial amount of the reactant

a - x = amount left after decay process  

a) concentration after 8.8 min:

8.8\times 60s=\frac{2.303}{6.7\times 10^{-4}s^{-1}}\log\frac{0.25}{a-x}

\log\frac{0.25}{a-x}=0.15

\frac{0.25}{a-x}=1.41

(a-x)=0.17M

b) for concentration to decrease from 0.25M to 0.15M

t=\frac{2.303}{6.7\times 10^{-4}s^{-1}}\log\frac{0.25}{0.15}\\\\t=\frac{2.303}{6.7\times 10^{-4}s^{-1}}\times 0.20

t=687s

7 0
3 years ago
Help Plzz Will give all points
ale4655 [162]

Answer:

reqirured mediem

Explanation:

5 0
3 years ago
Read 2 more answers
Sulfur and magnesium both have two valence electrons.<br> a. True<br> b. False
Nezavi [6.7K]
It would be false sulfur has 6 
3 0
3 years ago
If nitrogen (N) has 2 naturally occurring isotopes, nitrogen-14 (78.3%) and nitrogen-16 (21.7%), what is its average r.a.m.?
leva [86]

Answer:

14.434 r.a.m.

Explanation:

  • The atomic mass of an element is a weighted average of its isotopes in which the sum of the abundance of each isotope is equal to 1 or 100%.

∵ The atomic mass of N = ∑(atomic mass of each isotope)(its abundance)

∴ The atomic mass of N = (atomic mass of N-14)(abundance of N-14) + (atomic mass of N-16)(abundance of N-16)

atomic mass of N-14 = 14.0 r.a.m, abundance of N-14 = percent of N-14/100 = 78.3/100 = 0.783.

atomic mass of N-16 = 16.0 r.a.m, abundance of N-16 = percent of N-16/100 = 21.7/100 = 0.217.

∴ The atomic mass of N = (atomic mass of N-14)(abundance of N-14) + (atomic mass of N-16)(abundance of N-16) = (14.0 r.a.m)(0.783) + (16.0 r.a.m)(0.217) = 14.434 r.a.m.

5 0
3 years ago
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