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tankabanditka [31]
3 years ago
13

The equation shows one mole of ethanol fuel being burned in oxygen. Convert the energy released into its equivalent mass. C2H5OH

(l) + 3 O2(g) → 2 CO2(g) + 3 H2O (l) ΔH = -1418 kJ/mol
Chemistry
1 answer:
solong [7]3 years ago
4 0

Answer:

\boxed{\text{46.07 g}}

Explanation:

M_r:      46.07

         C₂H₅OH(ℓ) + 3O₂(g) ⟶ 2CO₂(g) + 3H₂O(ℓ); ΔH = -1418 kJ·mol⁻¹

\text{Mass} = \text{1418 kJ} \times \dfrac{\text{1 mol}}{\text{1418 kJ}} \times \dfrac{\text{46.07 g}}{\text{1mol}}= \textbf{46.07 g}\\\\\text{1418 kJ are equivalent to $\boxed{\textbf{46.07 g}}$ of ethanol}

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