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gayaneshka [121]
2 years ago
7

Find the 18th term of the arithmetic sequence- -2, -6, -10, -14

Mathematics
1 answer:
tresset_1 [31]2 years ago
3 0

Answer:

-2, -6, -10, -14, -18, -22, -26, -30, -34, -38, -42, -46, -50, -54, -58, -62, -66, -70

Step-by-step explanation:

The answer is -70.

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I NEED HELP ASAP PLZ!!!
polet [3.4K]

1. (7 , 0) and (11 , 3) → B and D

substitute each coordinate point into the left side of the equation and if equal to 21 then it is a solution.

( 7 , 0) → (3 × 7) - ( 4× 0)  = 21 - 0 = 21  

(11 , 3) → (3 × 11 )  - ( 4 × 3) = 33 - 12 = 21

2. ( 2 , - 9 ) is a solution to the equation

substitute the coordinates into the equation and if equal to 13 the it is the solution.

(2 , - 9 ) → (5 × 2 ) - (-9)/3 = 10 + 9/3 = 10 + 3 = 13

(3 , - 6) → (5 × 3) - (- 6)/3 = 15 + 6/3 = 15 + 2 = 17

thus (2 , -9 ) is the solution

4. x- intercept = (- 45 , 0)

to find the x- intercept let y = 0

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1/3x = - 15

multiply both sides by 3

x = 3 × - 15 = - 45

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3 years ago
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kipiarov [429]

Answer:

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Step-by-step explanation:

To solve this operation we need to find the common multiple of both denominators and solve for a.

\frac{3}{a+2} + \frac{4}{a-5} =\frac{3(a-5)+4(a+2)}{(a+2)(a-5)} =\frac{3a-15+4a+8}{(a+2)(a-5)} =\frac{7a-7}{(a+2)(a-5)} =\frac{7(a-1)}{(a+2)(a-5)}

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Step-by-step explanation:

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