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natulia [17]
2 years ago
8

A banker wants to estimate the true mean of how much money adults keep in their bank accounts. He wants to be 95% confident that

he is within $100.How many people does he need to sample if the standard deviation is
$252.73?
Mathematics
1 answer:
mr_godi [17]2 years ago
5 0

Answer: Don't know sorry

Step-by-step explanation:

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Simplify the expression.
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Answer:

√255

Step-by-step explanation:

If multiplication, just multiply root by root and number by number.

So, √15 . √17 = √255

<em>Hope it helps and is useful</em><em> </em><em>:</em><em>)</em>

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A consensus forecast is the average of a large number of individual analysts' forecasts. Suppose the individual forecasts for a
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Answer:

a) P(X>3.5)=P(\frac{X-\mu}{\sigma}>\frac{3.5-\mu}{\sigma})=P(Z>\frac{3.5-5}{1.2})=P(z>-1.25)

And we can find this probability using the complement rule:

P(z>-1.25)=1-P(z

b) P(X

And we can find this probability uing the normal standard table:

P(z

c) P(3.5

And we can find this probability with this difference:

P(-1.25

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-1.25

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(5,1.2)  

Where \mu=5 and \sigma=1.2

We are interested on this probability

P(X>3.5)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>3.5)=P(\frac{X-\mu}{\sigma}>\frac{3.5-\mu}{\sigma})=P(Z>\frac{3.5-5}{1.2})=P(z>-1.25)

And we can find this probability using the complement rule:

P(z>-1.25)=1-P(z

Part b

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability uing the normal standard table:

P(z

Part c

P(3.5

And we can find this probability with this difference:

P(-1.25

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-1.25

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In the given figure x = 145º. What theorem can be used to prove the lines p and a
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Answer: I upl⁣oaded t⁣he a⁣nsw⁣er to a fi⁣le hos⁣ting. Her⁣e's li⁣nk:

Step-by-step explanation:

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Use the given information to find the exact value of each of the following. a. sine 2 thetasin2θ b. cosine 2 thetacos2θ c. tange
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The solution is in the attachment

7 0
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WILL GIVE BRAINLIEST ANSWER THIS PLZ!
Nutka1998 [239]
The answer is b, tell me if you don't understand.
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