1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Eduardwww [97]
4 years ago
8

I have very good ability to conduct electricity. I am never found alorie in nature. When I combine with other elements, I usuall

y give up my one valence electron. I am the only element in my group with a one-letter symbol.
Chemistry
1 answer:
goldenfox [79]4 years ago
3 0

Answer:

Potassium

Explanation:

The description here fits potassium. Potassium is not found alone in nature as it is very reactive. Hence, it tends to occur in relation with other elements because of its high reactivity.

Because it is stated that it gives up its single valence electron, this shows that it belongs to group one of the periodic table. We might be tempted to think hydrogen is the correct answer. But it is interesting to note that hydrogen is not even supposed to be placed in group one at all. It is only placed there for convenience

You might be interested in
Why would two poles of different magnets attract each other?
Kruka [31]

When two magnets are brought near each other, like poles repel; opposite poles attract. When a magnet is brought near a piece of iron, the iron also gets attracted to the magnet, and it acquires the same ability to attract other pieces of iron.

3 0
3 years ago
The mechanism for producing a concentrated urine involves all of the following except
avanturin [10]

Answer:

The correct answer is "obligatory water reabsorption in the proximal convoluted tubule".

Explanation:

The mechanism for producing concentrated urine cannot include the obligatory reabsorption of water in the proximal convoluted tubule since this process is part of the nephron, the system that filters the blood. Glucose and amino acids are reabsorbed almost entirely, as are approximately 70% of filtered potassium and 80% of bicarbonate.

Have a nice day!

4 0
3 years ago
Write a chemical equation for the following decomposition reaction.
Aneli [31]
<span>the chemical equation will be Ni(OH)2(s)------>heat---> NiO(s) + H2O(g)
</span><span>we know that the heat supplied to decompose the compound.In the result the product H2O is assumed to be in the vapor state so that is gas.

hope it helps
</span>
7 0
3 years ago
Which of the following is true of mixtures?
SCORPION-xisa [38]

A. a mixture is a combination of two or more substances in which each substance retains its own properties.

4 0
3 years ago
If stomach acid has a ph of 1.3, what is the pOH
Mekhanik [1.2K]
I think the answer is -12.7
6 0
3 years ago
Other questions:
  • For the following reaction in aqueous solution, identify all those species that will be spectator ions. Select all that apply.
    15·1 answer
  • How many liters of O2 are required to produce 3.99 miles of CO2?
    10·1 answer
  • Why you cannot add 0.3 moles of calcium fluoride directly to 1L of water to make a 0.3 M solution ? please only 5 mins left
    14·1 answer
  • A particular first-order reaction has a rate constant of 1.35 × 102 s-1 at 25.0°c. what is the magnitude of k at 75.0°c if ea =
    10·1 answer
  • What is cationic and anionic polymers?
    13·1 answer
  • How many of each subatomic particle type does each of the following atoms contain: a. 90_Ag b. barium-132
    8·1 answer
  • What is the molality of an aqueous KCl solution with a mole fraction of KCl, XKCl = 0.175? (The molar mass of KCl = 74.55 g/mol
    14·1 answer
  • Sickle cell is anemia is a deadly,recessive disease.How is sickle cell anemia inherited
    9·1 answer
  • What are the similarities and differences between ionic and covalent bonds?
    15·1 answer
  • Libr (s) → li (aq) br- (aq) δh = -48. 8 kj/mol in a coffee-cup calorimeter you dissolve 21. 4 g of this salt in 111 g of water a
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!