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inn [45]
3 years ago
10

Round 0.41275 to the nearest thousandth

Mathematics
2 answers:
garri49 [273]3 years ago
4 0

Answer:

0.41300

Step-by-step explanation:

0.41275.

0.4: tenths place. 0.01: hundredths place. ...

Now look at the next decimal place, which is 0.0007: the ten thousandths place . This number determines whether the thousandths place will be rounded up or down. ...

Therefore, 0.41275 rounded to the nearest thousandth is:

dangina [55]3 years ago
3 0

Answer:

0.41, 2 is lower than 5 so we round down

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Find a ⋅ b. a = <5, 2>, b = <4, 5>
cestrela7 [59]

Answer:

  30

Step-by-step explanation:

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6 0
3 years ago
Given that α and β are the roots of the quadratic equation <img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20%2B6x-7%3Dp" id="Tex
siniylev [52]

Answer:

\large \boxed{\sf \ \ \ p=-11 \ \ \ }

Step-by-step explanation:

Hello,

\alpha \text{ and } \beta \text{ are the roots of the following equation}

   2x^2+6x-7=p

It means that

   2\alpha^2+6\alpha-7=p \\\\2\beta ^2+6\beta -7=p \\\\

And we know that

\alpha= 2\cdot \beta

So we got two equations

   2(2\beta)^2+6\cdot 2 \cdot \beta -7=p \\\\8\beta^2+12\beta -7=p\\\\ and \ 2\beta ^2+6\beta -7=p \ So \\\\\\8\beta^2+12\beta -7 = 2\beta ^2+6\beta -7\\\\6\beta^2+6\beta =0\\\\\beta(\beta+1)=0\\\\ \beta =0 \ or \ \beta=-1

For \beta =0, \ \ \alpha =0, \ \ p = -7

For \beta =-1, \ \ \alpha =-2, \ \ p= 2-6-7=-11, \ p=2*4-12-7=-11

I assume that we are after two different roots so the solution for p is p=-11

b) \alpha +2 =-2+2=0 \ and \ \beta+2=-1+2=1

So a quadratic equation with the expected roots  is

x(x-1)=x^2-x

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

3 0
3 years ago
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