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likoan [24]
2 years ago
7

Could someone help and explain their answer? (NO LINKS!) Thanks!

Mathematics
2 answers:
Harman [31]2 years ago
8 0

Answer:

5

Step-by-step explanation:

180

/\

<u>2</u> 90

/\

9 10

/\ /\

<u>3</u> <u>3</u> <u>2</u> <u>5</u>

180 = 2 × 3 × 3 × 2 × 5

2² × 3² × 5

NOTE: The numbers underlined in the factor tree are prime numbers.

Also, 2²is 4 (2 × 2)

3² is 9 (3 × 3)

4 × 9 = 36

36 × 5 = 180

Nonamiya [84]2 years ago
3 0

Answer:

5

Step-by-step explanation:

To find the prime factorization of a number, start by dividing the number by each prime number that you can divide by as many times as possible, starting with the smallest prime number and moving up. Then move on to the next prime number. The last division must give a quotient of 1. Then the prime factorization is the product of all the prime factors you divided the number by.

Here's how you use this method with 180.

Here are the first 10 prime numbers:

2, 3, 5, 7, 11, 13, 17, 19, 23, 29

Start by trying to divide by 2. 180 is divisible by 2.

180/2 = 90       90 is divisible by 2.

90/2 = 45         45 is not divisible by 2, so now try 3.

45/3 = 15          15 is divisible by 3.

15/3 = 5            5 is prime, so it is divisible by 5.

5/5 = 1              The divisors in bold are the prime factors of 180.

180 = 2 × 2 × 3 × 3 × 5

180 = 2² × 3² × 5

Answer: 5

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Use the exponential function y=500(.9)^x to find the value of the video game console after 4 years.
zysi [14]

Answer:

328.05 dollars

7 years

Step-by-step explanation:

1.

y=500(.9)^4 =328.05

What is being asked in the problem and what does that mean?

We are asked to the price of the video game after 4 years.

What do I know and what does it mean? What plan am I going to try?

We know the <u>initial price is $500</u>, the <u>value depreciates 10% each year </u>because we have .9 or 90% of the price going into the next year.

- value of the video game after first year 90% of 500 so is 450

- value of the video game after second year 90% of 450 so is 405

-value of the video game after third year 90% of 405 so is 364.5

-value of the video game after <u>fourth year</u> 90% of 364.5 so is 328.05

The plan is to substitute x with 4 and calculate y, y=500(.9)^4

What is your answer and what does it mean?

The answer is $328.05, and it means that the video game that was initially worth $500 it lost its' value by 10 % each of the four years.

2.

         y= 500(.9)^x

----------------------------------------------------------------------------

x =8, y= 500(0.9)^8 = 215.234 ≈215.23, this is less than $250

x = 7, y= 500(0.9)^7 = 239.148 ≈239.15, this is less than $250

x =6, y= 500(0.9)^6 = 265.721 ≈ 265.72, this is more than $250

What is being asked in the problem and what does that mean?

We are asked to find the value of x that represents the years such that the value of the console is still under $250.

What do I know and what does it mean? What plan am I going to try?

We know the value of y has to be less that $250, we know the inequality

[500(.9)^x ] < 250, the plan is to try different values for x until we have the maximum value of x that gives us less than 250.

8 0
3 years ago
If y = 12 x – 12, determine the value of y when x = –16.
GrogVix [38]

Answer:

Step-by-step explanation: y=180

4 0
3 years ago
Can anyone please help me with this!!! :(
UkoKoshka [18]

Answer:

ano ba gagawin

parang Ang Dali pero ano gagawin dyan

3 0
2 years ago
Read 2 more answers
Help find the area, please.
Tanzania [10]
The answer is 72 !! :)
3 0
3 years ago
The antibiotic clarithromycin is eliminated from the body according to the formula A(t) = 500e−0.1386t, where A is the amount re
PolarNik [594]

Answer:

Time(t) = 11.61 hours (Rounded to two decimal place)

Step-by-step explanation:

Given: The antibiotic  clarithromycin is eliminated from the body according to the formula:

A(t) = 500e^{-0.1386t}                 ......[1]

where;

A - Amount remaining in the body(in milligram)

t - time in hours after the drug reaches peak concentration.

Given: Amount of drug in the body is reduced to 100 milligrams.

then,

Substitute the value of A = 100 milligrams in [1] we get;

100= 500e^{-0.1386t}

Divide both sides by 500 we get;

\frac{100}{500}=\frac{ 500e^{-0.1386t}}{500}

Simplify:

\frac{1}{5} = e^{-0.1386t}

Taking logarithm both sides with base e, then we have;

\log_e (\frac{1}{5})= \log_e (e^{-0.1386t})

\log_e (\frac{1}{5})=-0.1386t         [ Using \log_e e^a =a ]

or

\log_e (0.2)=-0.1386t

-1.6094379124341 = -0.1386t

 [using value of \log_e (0.2) = -1.6094379124341 ]

then;

t = \frac{-1.6094379124341}{-0.1386}

Simplify:

t ≈11.61 hours.

Therefore, the time 11.61 hours(Rounded two decimal place) will pass before the amount of drug in the body is reduced to 100 milligrams


6 0
2 years ago
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