I have to form a couple of equations in order to solve it.
let the amount of soybean in the mixture be x and that of cornmeal be y
Step-by-step explanation:
x+y = 280
y = 280 - x
x*(14/100) + y*(7/100) = 280*(12/100)
Multiplying the whole equation by 100;
14x + 7y = 3360
in this equation,put y = 280 - x
14x +7 (280-x) = 3360
14x +1960 - 7x = 3360
14x - 7x = 3360 - 1960
7x = 1400
x = 200lbs
y = 280 - x
= 280 - 200
= 80 lbs
Inorder to make a 280lbs mixture having 12% protein, we should mix 200lbs of soyabean and 80 lbs of cornmeal
Answer:
Perimeter of rectangle = 6√10 units (the attachment isnt clear. It seems the answer is in option B)
Step-by-step explanation:
First we find the distance of the length and width of the rectangle.
Distance between E and F = Distance EF
Distance EF = √(∆y²-∆x²)
= √[(5-7)² + (1-7)²] = √[(-2)² + (-6)²]
= √(4+36) = √40
Distance EF = 2√10
Distance between F and G = Distance FG
Distance FG = √(∆y²-∆x²)
= √[(2-5)² + (2-1)²] = √[(-3)² + (1)²]
= √(9+1) = √10
Distance FG = √10
Length= distance EF = distance HG
And width = distance FG = distance EH
Perimeter of rectangle = 2(length + width)
Perimeter of rectangle = 2(2√10 + √10)
= 2(3√10)
Perimeter of rectangle = 6√10 units (the attachment isnt clear. It seems the answer is in option B)
Answer:
C :)
Step-by-step explanation:
Answer:
21. An= 100 (2)^n-1
22. $51,200
23. n= 15
Step-by-step explanation:
21. 100, 200, 400, 800, 1600...
An= A r ^n-1
22. a10= 100(2)^10-1
a10= 100(2)^9
23. n=14
a14= 100(2)^14-1= 819200
n= 15
a15= 100(2)^15-1= 1638400
Answer:
15
Step-by-step explanation:
16 % (2/5 + 2/3) = 16 % (6/15 + 10/15) = 16 % 16/15 = 16/1 x 15/16 = 240 % 16 = 15
