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3 years ago

8

sand is falling off a conveyor in a conical pile at a constant rate of 2 cubic yards per minute. The height of the sand is equal

to the radius of the pile of sand on the ground. If the cone-shaped pile is 3 feet tall now, how tall will it be in one hour?

2 answers:

kvv77 [185]3 years ago

7 0

The volume of a cone is (1/3)πr2h.

In this problem r=2h or h=(1/2)r

Hence V = (1/6)πr3

dV/dt = (1/2)πr2 dr/dt

With this information you should now be able to answer the question. Remember the relation between r and h!

never mind i was right

im also so sorry if you dont understand or its not one of the answers

PolarNik [594]3 years ago

3 0

Answer:

t a sand and gravel plant, sand is falling off a conveyor, and onto a conical pile at a rate of 10 cubic feet per minute. The diameter of the base of the cone is approximately three times the altitude. At what rate is the height of the pile changing when the pile is 15 feet high?

Step-by-step explanation:

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Write an equivalent expression for the expression shown below:<br><br> a/3 + a/3 + a/3

iris [78.8K]

Answer:

3 (a/3) = a

Step-by-step explanation:

a/3 + a/3 + a/3

3 times a/3

the 3's cancel each other out

A

Keep up the good work! =)

3 0

4 years ago

A guy wire 30 ft long supports an antenna at a point that is 24 ft above the base of the antenna.

GalinKa [24]

Use Pythagorean Theorem
c2 = a2 + b2
152 = a2 + 12
a2 = 152 - 122
=225 - 144 = 81
a = 9 ft
Distance from base of antenna = 9ft

4 0

2 years ago

4/25, 13%, 0.28, 7%, 21/100, 0.15 least to greatest

Katarina [22]

7%, 13%, 0.15, 4/25, 21/100, 0.28

5 0

3 years ago

Read 2 more answers

If 1st and 4tg terms of G.p are 500 and 32 respectively it's second term is ?

bixtya [17]

Answer:

$T_{2} = 200$

Step-by-step explanation:

Given

Geometry Progression

$T_1 = 500$

$T_4 = 32$

Required

Calculate the second term

First, we need to write out the formula to calculate the nth term of a GP

$T_n = ar^{n-1}$

For first term: Tn = 500 and n = 1

$500 = ar^{1-1}$

$500 = ar^{0}$

$500 = a$

$a = 500$

For fought term: Tn = 32 and n = 4

$32 = ar^{4-1}$

$32 = ar^3$

Substitute 500 for a

$32 = 500 * r^3$

Make r^3 the subject

$r^3 = \frac{32}{500}$

$r^3 = 0.064$

Take cube roots

$\sqrt[3]{r^3} = \sqrt[3]{0.064}$

$r = \sqrt[3]{0.064}$

$r = 0.4$

Using: $T_n = ar^{n-1}$

$n = 2$ $r = 0.4$ and $a = 500$

$T_{2} = 500 * 0.4^{2-1}$

$T_{2} = 500 * 0.4^1$

$T_{2} = 500 * 0.4$

$T_{2} = 200$

<em>Hence, the second term is 200</em>

5 0

3 years ago

A store was selling lawn mowers for $69. The repair

Natali5045456 [20]

Answer:

$84.87

Step-by-step explanation:

The mover costs $69

23% of 69 is $15.87

add the two together to get $84.87

(or just multiply 69 by 1.23)

5 0

3 years ago

Read 2 more answers