sand is falling off a conveyor in a conical pile at a constant rate of 2 cubic yards per minute. The height of the sand is equal to the radius of the pile of sand on the ground. If the cone-shaped pile is 3 feet tall now, how tall will it be in one hour?
2 answers:
The volume of a cone is (1/3)πr2h.
In this problem r=2h or h=(1/2)r
Hence V = (1/6)πr3
dV/dt = (1/2)πr2 dr/dt
With this information you should now be able to answer the question. Remember the relation between r and h!
never mind i was right
im also so sorry if you dont understand or its not one of the answers
Answer:
t a sand and gravel plant, sand is falling off a conveyor, and onto a conical pile at a rate of 10 cubic feet per minute. The diameter of the base of the cone is approximately three times the altitude. At what rate is the height of the pile changing when the pile is 15 feet high?
Step-by-step explanation:
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Answer:
your answer is going to be B: Obtuse
I think it’s 74 bc I got it right but your might be different
The expression that can be used to represent x is not shown.
The answer is D
Hello from MrBillDoesMath!
Answer: 70%
Discussion:
Goal = 5000
Amount raised = 3500
Percent of goal reached = ( 3500/5000) * 100 =
0.7 * 100 = 70
Thank you,
MrB
