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2 years ago

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A bicycle takes 8.0 seconds to accelerate at a constant rate from rest to a speed of 4.0 m/s. If the mass of the bicycle and rid

er together is 85 kg, what is the net force acting on the bicycle

1 answer:

yanalaym [24]2 years ago

6 0

11.0 second hope i helped

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5. Which type of energy resource is hamessed beneath the Earth's surface? A. biomass B.solar C.hydroelectric D.geothermal

Elan Coil [88]

<u><em>It's called geothermal energy, and is present due to the incredible amount of heat present in Earth's interior from radioactive decay, friction, and residual heat from Earth's formation.</em></u>

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2 years ago

A student finds an unlabeled liquid container in his lab. He notices that the container has two liquids. Since the two liquids h

raketka [301]

Answer:

$\rho = 1848.03 kg m^{-3}$

Explanation:

given data:

density of water \rho = 1 gm/cm^3 = 1000 kg/m^3

height of water = 20 cm =0.2 m

Pressure p = 1.01300*10^5 Pa

pressure at bottom

$P = P_{fluid} + P_{h_2 o}$

$P = P_{fluid} + \rho g h$

$P_{fluid} = P - \rho g h$

= 1.01300*10^5 - 1000*0.2*9.8

= 99340 Pa

$p_{fluid} = P_{atm} + \rho g h_{fluid}$ h_[fluid} = 0.307m

$99340 = 104900 + \rho *9.8*0.307$

$\rho = 1848.03 kg m^{-3}$

5 0

3 years ago

A cylinder with a radius of 11 cm and a height of 3.4 cm has a mass of 10.0 kg. What is the weight of this cylinder?

Irina-Kira [14]

Answer:

98.1

Explanation:

7 0

2 years ago

Read 2 more answers

A bird is standing on an electric transmission line carrying a large amount of current. Find the power dissipated by the bird If

iren [92.7K]

P = 7.3 × 10^-13 Watt

Explanation:

First of all, are you sure that what you have is the right answer?

Anyway, the definition of power dissipated is given by

P = I^2×R

where I is the current and R is the resistance. But we also know from Ohm's law that

V = IR

so we can rewrite the equation for power P as

P = I^2R = I(IR) = VI

= (0.0054 volt)(1.35 × 10^-10 A)

= 7.3 × 10^-13 Watt

3 0

2 years ago

Starting from rest, a disk rotates about its central axis with constant angular acceleration. In 8.00 s, it rotates 17.5 rad. Du

diamong [38]

Answer

Given,

time = 8 s

θ = 17.5 rad

initial angular velocity = 0 rad/s

Using rotational motion equation

$\theta=\omega_{0} t+0.5 \alpha t^{2}$

$17.5=0+0.5 \alpha(8)^{2}$

$\alpha = 0.546 \ rad/s^2$

a. angular acceleration $\alpha=0.546 \ rad/s^2$

b. Average angular velocity = total angle/total time taken

= $\dfrac{17.5}{8}$ = 2.187 rad/s

c. we have,

$\omega=\omega_{0}+a t$

$=0+0.546 \times 8$

Angular velocity at end of 8 seconds $=\omega=4.368$ rad/s

d. we have, additional angle in next 8 seconds:

$\theta=\omega_{0} t+0.5 \alpha {t}^{2}$

$=4.368 \times 8+0.5 \times 0.546 \times 8^{2}$

$=52.416$ rads

8 0

3 years ago