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What is the period of a wave with a frequency of 100 Hz and a wavelength of 2.0 m

spin [16.1K]

The answer for the following answer is answered below.

Therefore the time period of the wave is 0.01 seconds.
Therefore the option for the answer is "B".

Explanation:

Frequency (f):

The number of waves that pass a fixed place in a given amount of time.

The SI unit of frequency is Hertz (Hz)

Time period (T):

The time taken for one complete cycle of vibration to pass a given point.

The SI unit of time period is seconds (s)

Given:

frequency (f) = 100 Hz

wavelength (λ) = 2.0 m

To calculate:

Time period (T)

We know;

According to the formula;

f = $\frac{1}{T}$

Where,

f represents the frequency

T represents the time period

from the formula;

T = $\frac{1}{f}$

T = $\frac{1}{100}$

T = 0.01 seconds

Therefore the time period of the wave is 0.01 seconds.

5 0

2 years ago

Read 2 more answers

If you exert a force of 100.0 N to lift a box a distance of 0.5 m, how much work do you do? 200 J 400 J 50 J 26 J

jeyben [28]

Work = force x distance
= 100N (force) x 0.5m (distance)
= 50J

4 0

3 years ago

A rocket burns fuel as it shoots into the sky. What happens to the mass and volume of the rocket?

diamong [38]

Answer:

mass goes down volume remains the same

6 0

2 years ago

Please help !

BartSMP [9]

Answer:

2179412787.20000

4 0

3 years ago

The drawing shows a person (weight W = 588 N, L1 = 0.838 m, L2 = 0.398 m) doing push-ups. Find the normal force exerted by the f

zhenek [66]

Complete Question

The complete question is shown on the first uploaded image

Answer:

Force on each hand is 196.22 N

Force on each foot is 95.8 N

Explanation:

In order to get a better understanding of this question let us explain some concepts

Normal Force:

We can define normal force Fn as that type of force which makes a 90 degree angle with the surface on which it is exerted.

Torque:

We can define torque as the moment of forces that tends to produce or cause rotation

From the question we are given that

Weight of body is (W) = 584 N

The normal force on both hands (Ha) = ?

The normal force on both legs (Lg) = ?

Looking at the diagram the person is at equilibrium so

584 = Ha + Lg

an also this mean that torques acting on the body is balanced

So, 0.410 Ha = 0.840 Lg

Making Lg the subject of formula in the equation above we

Lg = 0.4881 Ha

Considering the first equation and replacing Lg with this recent equation we have

584 = Ha + 0.4881 Ha

Therefore Ha = 392.44 N

This value obtained is for both hands for each hand we divide by 2

Therefore we have for each hand $= 392.44/2$ =196.55 N

Since we have been able to get the force on both hands we can substitute it in to the equation where we made Lg the subject of formula and we have

Lg = 0.4881 × 392.44

= 191.22 N

The value above is the force on both legs to obtain the force on each leg we have

191.22/2 = 95.8 N.

8 0

3 years ago