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Oliga [24]
4 years ago
7

If carbon has an atomic number of 6, how many protons and neutrons are found in the carbon-14 atom? A.

Physics
1 answer:
Alex Ar [27]4 years ago
5 0
The correct answer is B. 6 protons and 8 neutrons

Carbon-14 has same atomic number of 6. It has a nucleon number of 14
Atomic number = proton number = 6
Neutron number = nucleon number - atomic number = 14 - 6 = 8

Hope it helped!
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A gamma-ray photon produces an electron and a positron, each with a kinetic energy of 261 keV . h=6.626×10−34J⋅s, c=2.998×108m/s
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Answer:

The energy and the wavelength of the photon are 1.546 MeV and 8.036\times10^{-13}\ m.

Explanation:

Given that,

Kinetic energy = 261 KeV

Planck's constant h = 6.626\times10^{−34}\ J.s

Speed of light c=2.998\times10^{8}\ m/s

Mass of electron m_{e}=9.109\times10^{-31}\ kg

Charge q=1.602\times10^{-19}\ C

(A). We need to calculate the energy of the photon

Using formula of rest mass energy

E=m_{0}c^2

E=9.109\times10^{-31}\times(3\times10^{8})^2

E=8.198\times10^{-14}\ J

Energy in eV

E=\dfrac{8.198\times10^{-14}}{1.6\times10^{-19}}

E=512375\ eV

E=0.512\ MeV

The total energy of photon

TE=2(E+K.E)

TE=2(0.512+0.261)

TE=1.546\ MeV

(B). We need to calculate the wavelength of the photon

Using formula of wavelength

\lambda=\dfrac{hc}{E}

Put the value into the formula

\lambda=\dfrac{6.626\times10^{−34}\times3\times10^{8}}{1.546\times10^{6}\times1.6\times10^{-19}}

\lambda=8.036\times10^{-13}\ m

Hence, The energy and the wavelength of the photon are 1.546 MeV and 8.036\times10^{-13}\ m.

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