All categories

3 years ago

If carbon has an atomic number of 6, how many protons and neutrons are found in the carbon-14 atom? A.

1 answer:

5 0

The correct answer is B. 6 protons and 8 neutrons

Carbon-14 has same atomic number of 6. It has a nucleon number of 14
Atomic number = proton number = 6
Neutron number = nucleon number - atomic number = 14 - 6 = 8

Hope it helped!

You might be interested in

A. How does increasing the voltage of a power supply in an electromagnet affect the strength of the magnetic field?

seropon [69]

PART A)

If we increase the voltage supply in an electromagnet then it will increase the current that is flowing in it

So here due to increase in current there will be increase in the magnetic field due to that electromagnet

PART B)

Here in electric generator the current is produced by rotating a coil between two strong magnets.

So here mechanical energy of rotation of coil is converted into electromagnetic energy.

PART C)

Step up transformer convert the lower voltage input into higher voltage output

here number of turns of coil in output side or secondary number of coils is more than the number of coils in primary side or input side

PART D)

Force on a moving charge is given by

$F = q(\vec v \times \vec B)$

here we know that

q = 0.000600 C

$v = 2.8 \times 10^5 m/s$

B = 4.21 T

now from above equation we have

$F = 0.0006(2.8\times 10^5)(4.21)$

$F = 707.3 N$

direction of force is given by right hand thumb rule

using that rule we got force downwards

7 0

3 years ago

Read 2 more answers

Help asap

n200080 [17]

Answer:

magma

Explanation:

I wanna think that that's right if it's not in so sorry but I'm pretty sure it's magma

6 0

3 years ago

A constant force of 45 N directed at angle θ to the horizontal pulls a crate of weight 100 N from one end of a room to another a

Rasek [7]

Answer:

$W=173.48J$

Explanation:

information we know:

Total force: $F=45N$

Weight: $w=100N$

distance: $4m$

vertical component of the force: $F_{y}=12N$

-------------

In this case we need the formulas to calculate the components of the force (because to calculate the work we need the horizontal component of the force).

horizontal component: $F_{x}=Fcos\theta$