Answer:
Step-by-step explanation:
This is an incomplete problem. Other data were not given.
Given:
Profit of every sandwich = $2
Profit of every wrap = $3
x = sandwich
y = wrap
Last month: 2x + 3y = 1,470
Next month: 2x + 3y = 1,593
Based on the given equation:
Both still have the same profit. $2 for sandwiches and $3 for wraps.
The only reason why there is a difference in the total amount is the change in the number of sandwich or wrap sold in a given month.
Since, next month's total sale is higher than last month's total sale, it is safe to assume that the sale of sandwich or wrap is higher than last month's sale.
Given that R(ABCDE) is in Boyce-Codd normal form.
And AB is the only key for R.
Definition
A relational nontrivial Schema R is in BCNF if FD (X-A) holds in R, Super key of R. whenever then X is
a
Given that AB is the only key for R.
ABC E (Yes).
check if ABC is a Super key. AB is a key, ABC is A B C E is in BONE a super key.
2) ACE B
(NO). no Check if ACE As there is ACE is not a Super key? AB in Super key. ACE.
ACE B
is
Boyce-Codd Normal Form not in BENE (NO)
3) ACDE → B (NO)
check if is a super key. ACDE
As ACDE there is not any AB Tn ACDE. a super key.
ACDEB is not in BCNF.
4) BS → C → (NO)
As there is no AB in BC ~. B(→ not in BCNF
BC is not a super key.
5) ABDE (Yes).
Since AB is a key.
ABO TS a super key.
.. ABDE → E is in BCNF
Let R(ABCDE) be a relation in Boyce-Codd Normal Form (BCNF). If AB is the only key for R, identify each of these FDs from the following list. Answer Yes or No and explain your answer to receive points.
1. ABC E
2. ACE B
3. ACDE B
4. BC C
5. ABD E
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Answer:
a2+b2=c2
Step-by-step explanation:
10(2)+12(2)=244
Answer:
p=£800
r=5%
t=3years
Step-by-step explanation:
simple interest=ptr/100=£800×5×3/100=£120
