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2 years ago

I asked this already but please solve this NO LINKS

Mathematics

2 answers:

brilliants [131]2 years ago

3 0

Answer:

-4x^3+12x^2-1

Step-by-step explanation:

QveST [7]2 years ago

3 0

We have (-4x^3+2x^2-9) + 2(5x^2+4)
= -4x^3 + 2x^2 - 9 + 10x^2 + 8
= -4x^3 + 12x^2 - 1

Ok done. Thank to me:>

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2 years ago

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statuscvo [17]

Answer:

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Step-by-step explanation:

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2 years ago

Input the equation of the given line in slope-intercept form. the line with m=2 and b=-4

love history [14]

Answer:

Step-by-step explanation:

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3 years ago

To determine what percentage of 376 teachers at a university were female, Ryan randomly selected 14 teachers. He then collected

Kipish [7]

Answer:

a)There are 14 teachers in Ryan's sample, and 362 teachers in the population.

Step-by-step explanation:

Population:-

The totality of observations with which we are concerned, whether this number be finite or infinite is called population.

Given data population is 376 teachers at a university were female'

Sample:-

A sample is a subset of a Population

sample of given data = 14teachers

The percentage of 376 teachers at a university were female, Ryan randomly selected 14 teachers.

$p = \frac{14}{376} = 0.0372$ = 3.72%

6 0

3 years ago

help solve this problem Based on a poll, 62% of Internet users are more careful about personal information when using a public

erma4kov [3.2K]

Answer

The probability that among four randomly selected Internet users, at least one is more careful about personal information when using a public Wi-Fi hotspot is 0.979.

Step-by-step explanation:

Since 62% of Internet users are more careful about personal information when using a public Wi-Fi hotspot.

Therefore, the Probability of 62% of Internet users are more careful about personal information when using a public Wi-Fi hotspot is, p=0.62.

We have to find the probability that at least one user is more careful about personal information when using wi-fi hotspot.

Probability of internet users are not more careful about personal information when using a public wi-fi hotspot, i.e $q=1-p$

$q=1-0.62=0.38$

Use Binomial Distribution, i.e, $P\left ( X \right )=^nC_xp^xq^\left ( n-x \right )$

p=0.62, q=0.38, n=4.

Required Probability $P\left ( X\geq 1 \right )=P\left ( X=1 \right )+P\left ( X=2 \right )+P\left ( X=3 \right )+P\left ( X=4 \right )$

$P\left ( X\geq 1 \right )=1-P\left ( X=0 \right )$

=1- $^4C_0p^0q^\left ( 4-0 \right )$

=1- $4\cdot1\cdot q^\left ( 4-0 \right )$

=1- $4\cdot \left ( 0.38 \right )^4$

=1-0.02085136=0.97914864

Therefore, the probability that at least one users more careful about personal information when using wi-fi hotspot, i.e 0.979(approx).

RESULT:

The result should not be impacted by this because volunteers are likely to have the most relevant responds.

6 0

2 years ago