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agasfer [191]
3 years ago
14

I asked this already but please solve this NO LINKS

Mathematics
2 answers:
brilliants [131]3 years ago
3 0

Answer:

-4x^3+12x^2-1

Step-by-step explanation:

QveST [7]3 years ago
3 0
We have (-4x^3+2x^2-9) + 2(5x^2+4)
= -4x^3 + 2x^2 - 9 + 10x^2 + 8
= -4x^3 + 12x^2 - 1

Ok done. Thank to me:>
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Which statement is correct?
iragen [17]

Answer:

I think its OB but I'm not sure

Step-by-step explanation:

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2 years ago
Five friends buy tickets to a carnival. They each also spend $4 on a funnel cake. They spent a total of $60. How much does one t
Butoxors [25]

Answer:

$8 for each tickets

Step-by-step explanation: 60/5 equals 12

Each friends have $12

12-4=8

Each ticked cost 8 dollars.

4 0
2 years ago
John made a small rectangular table for his workroom. If the sides of the table are 32 inches and 26 inches, what should the tab
matrenka [14]

Answer:

The table should measure diagonally about 41.23 inches.

Step-by-step explanation:

To find the diagonal of a rectangle we use the formula :

a^{2} + b^{2} = c^{2}

A and B both represent the side lengths of the rectangle, while C is the diagonal part. Knowing this formula, let's plug in the values for A and B and see what happens.

32^{2} + 26^{2} = c^{2}

1024 + 676 = c^{2}

1700 = c^{2}

The square root of 1700 is (rounded to the hundreth's place) = 41.23

6 0
2 years ago
If x equals 4 what is the value of y in the example below <br><br> y= 1/4 4.
ddd [48]

Answer:

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Step-by-step explanation:

6 0
3 years ago
Find the domain of the function. (Enter your answer using interval notation.)
Andreas93 [3]

Answer:

(-\infty,-9)\cup(-9,\infty)

Step-by-step explanation:

The domain of a rational function is all real numbers <em>except </em>for when the denominator equals 0.

So, to find the domain restrictions, set the denominator to 0 and solve for x.

We have the rational function:

s(y)=\frac{7y}{y+9}

Set the denominator to 0:

y+9=0

Subtract 9:

y\neq-9

So, the domain is all real numbers except for -9.

In other words, our domain is all values to the left of negative 9 and to the right of negative 9.

In interval notation, this is:

(-\infty,-9)\cup(-9,\infty)

And we're done :)

4 0
3 years ago
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