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Ira Lisetskai [31]
2 years ago
9

Enzymes transferring electrons at the start of the ETS are referred to as ________, whereas enzymes transferring electrons to th

e terminal electron acceptor are designated as ________.Question 40 options:a) sulfatases; nitrogenasesb) lyases; hydrolasesc) permeases; proton pumpsd) dehydrogenases; oxidasese) oxidases; dehydrogenases
Biology
1 answer:
aev [14]2 years ago
8 0

Answer:

dehydrogenases; oxidases

Explanation:

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Name two models used<br> to show the transfer of<br> energy in an ecosystem
aleksandr82 [10.1K]

Answer:

Flow of Energy can be explained by means of two models namely: single channel energy model and Y-shaped energy model.

Hope this helps :)

3 0
3 years ago
Which of the following statements about the monomers and polymers found in living organisms is
hodyreva [135]

Answer: Option C is false.

Explanation:

Hydrolysis is the breakdown of compounds(polymers) into simpler substances(monomers) using water. Monomers on the other hand are joined together by a process called dehydration synthesis or polymerization, where the hydroxyl group of one monomer binds to the other, forming a covalent bond.

7 0
3 years ago
If you use a millimeter to measure something you are measuring what?
laila [671]

Answer:

the anwer is distance option a or 1

8 0
2 years ago
Briefly describe how amniocentesis and chorionic villi sampling are used in genetic screening.
bearhunter [10]

Answer:

Amniocentesis is an invasive method that involves the aspiration of 10-20 ml of fetal water through the abdominal wall under ultrasound-guided control. In most cases, the procedure is performed around the 16th week of gestation. The fetal water sample contains fetal cells, mostly cells of fetal skin and the epithelium of the urinary tract.

Chorionic Villus Sampling (CVS) biopsy is performed between weeks 11 and 12 of gestation. During biopsy, with ultrasound guidance, the tissue of the chorionic fossa is aspirated mainly across the abdomen (transabdominal pathway). The biopsy specimen is of fetal origin and belongs to the outer layer of blastocyst cells or the trophoblast (outer layer of the placenta). Very often, the biopsy specimen contains tissue of the decidua (mucous membrane of the uterus) that is of maternal origin, and it is necessary to remove the maternal tissue before any treatment of the sample.

Explanation:

The amniocentesis procedure carries a risk of miscarriage of 0.5-1%.  After aspiration of the fruit of the water, the sample is centrifuged to separate the cells from the amniotic fluid. Separate cells are seeded on a nutrient medium (cell culture) that stimulates cell growth. After about 14 days, the cell culture is further used for various genetic or biochemical analyzes such as karyotyping.

The advantage of chorionic biopsy is the amount of biological material, which is sufficient for the whole a number of different laboratory procedures. Also, a great advantage is the timing of the procedure as it allows diagnosis in the first trimester of pregnancy, but the chorionic biopsy procedure itself carries a risk of miscarriage of 1-2%.

3 0
3 years ago
A population of 150 individuals has an allele frequency of 0.2 for the dominant allele (H) and a frequency of 0.8 for the recess
Amanda [17]
Hardy-Weinberg Equation (HW) states that following certain biological tenets or requirements, the total frequency of all homozygous dominant alleles (p) and the total frequency of all homozygous recessive alleles (q) for a gene, account for the total # of alleles for that gene in that HW population, which is 100% or 1.00 as a decimel. So in short: p + q = 1, and additionally (p+q)^2 = 1^2, or 1
So (p+q)(p+q) algebraically works out to p^2 + 2pq + q^2 = 1, where p^2 = genotype frequency of homozygous dominant individuals, 2pq = genotype frequency of heterozygous individuals, and q^2 = genotype frequency of homozygous recessive individuals.
The problem states that Ptotal = 150 individuals, H frequency (p) = 0.2, and h frequency (q) = 0.8.
So homozygous dominant individuals (HH) = p^2 = (0.2)^2 = 0.04 or 4% of 150 --> 6 people
Heterozygous individuals (Hh) = 2pq = 2(0.2)(0.8) = 0.32 or 32% of 150
--> 48 people
And homozygous recessive individuals (hh) = q^2 = (0.8)^2 = 0.64 = 64% of 150 --> 96 people
Hope that helps you to understand how to solve these types of population genetics problems!
6 0
2 years ago
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