The interval where the function is nonlinear and decreasing is 0 < x < 4
<h3>How to determine the interval where the function is nonlinear and decreasing?</h3>
The straight lines on the graph are the intervals where the graph is linear
This means that the straight lines on the graph will not be considered
Considering the curve, the graph decrease from x = 0 to x = 4
This can be rewritten as:
0 < x < 4
Hence, the interval where the function is nonlinear and decreasing is 0 < x < 4
Read more about function intervals at:
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Answer:
8w^2 I don't know why it is not on here, but I put it in an algebra calculator and everything. Good luck. :)
Step-by-step explanation:
Simply the radicals by multiplying and taking square roots.
2
*
= 2
*2w![\sqrt[4]{2w}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B2w%7D)
= 4w![\sqrt[4]{16w^4}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B16w%5E4%7D)
=4w(2w)
=
Collect like terms
2n2 i’m gonna assume is 2n^2
and n2 is 2n
2n^2-10n+5
So the equation you'll use is (18,000 × .041)y+18000. Y is your years which is 20. So all you need to do is plug it in to get (18,000 × .041)20+18000 and when solved is 32,760 downloads by 2030
Answer 28.
Possible values for the three factors of -3
- 1, -1 and 3
- -1.5, 1 and 2
- 1.5, -1 and 2
- 1.5, 1 and -2
Answer 29.
The product of two nonzero integers will be less than or equal to both of the integers if they are multiplied by number itself and one or by number itself and one with negative sign.
Answer 30.
The sign of the product of three integers with the same sign will be positive or negative. If odd number of same sign is multiplied, the product will be of that sign.
(+) (+) (+) = (+)
(-) (-) (-) = (-)