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3 years ago

A. 6.084 x 103 B. 6.084 x 10-6 C. 6.084 x 10-3 O D. 6.084 x 106

Physics

1 answer:

Veseljchak [2.6K]3 years ago

5 0

Answer:

Explanation:

I'm just guessing I'll be honest I don't know

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Deimos's Orbit. Deimos orbits Mars at a distance of 23,460 km from the center of the planet and has a period of 1.263 days. Assu

mihalych1998 [28]

Answer:

M = 5.882 10²³ kg

Explanation:

Let's use Newton's second law to analyze the satellite orbit around Mars.

F = m a

force is universal attraction and acceleration is centripetal

a = v²/ R

the modulus of velocity in a circular orbit is constant

v= d/T

the distance of the cicule is

d =2pi R

a = 2pi R/T

we substitute

- G m M / R² = m ( $- \frac{4\pi^2 R^2 }{T^2 R}$ )

G M = $\frac{ 4\pi ^2 R^3 }{T^2 }$

M = $\frac{4 \pi ^2 R^3 }{ G T^2 }$

the distance R is the distance from the center of the planet Mars to the center of the satellite Deimos

R = 23460 km = 2.3460 10⁷ m

the period of the orbit is

T = 1,263 days = 1,263 day (24 h / 1 day) (3600s / h)

T = 1.0912 10⁵ s

let's calculate

M = $\frac{4 \pi ^2 ( 2.3460 \ 10^7)^3 }{5.67 10^{-11} \ (1.0912 \ 10^5)^2 }$

M = 509.73418 10²¹ /8.66640 10⁻¹

M = 58.817 10²² kg

M = 5.882 10²³ kg

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3 years ago

The key to generating electricity from coal is the generation of _______.

expeople1 [14]

Answer:

The generation of <u>heat</u>.

Explanation:

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3 years ago

How to solve a torque problem

podryga [215]

<span>you must first select an axis of rotation about which to calculate moment arms and torques. </span>

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3 years ago

A 28.0 kg child plays on a swing having support ropes that are 2.30 m long. A friend pulls her back until the ropes are 45.0 ∘ f

Dimas [21]

Answer

A)184.9J

B)=3.63m/s

C) Zero

Explanation:

A)potential energy of the child at the initial position, measured relative the her potential energy at the bottom of the motion, is

U=Mgh

Where m=28kg

g= 9.8m/s

h= difference in height between the initial position and the bottom position

We are told that the rope is L = 2.30 m long and inclined at 45.0° from the vertical

h=L-Lcos(x)= L(1-cosx)=2.30(1-cos45)

=0.674m

Her Potential Energy will now

= 28× 9.8×0.674

=184.9J

B)we can see that at the bottom of the motion, all the initial potential energy of the child has been converted into kinetic energy:

E= 0.5mv^2

where

m = 28.0 kg is the mass of the child

v is the speed of the child at the bottom position

Solving the equation for v, we find

V=√2k/m

V=√(2×184.9/28

=3.63m/s

C)we can find work done by the tension in the rope is given using expresion below

W= Tdcosx

where W= work done

T is the tension

d = displacement of the child

x= angle between the directions of T and d

In this situation, we have that the tension in the rope, T, is always perpendicular to the displacement of the child, d. x= 90∘ and cos90∘=0 hence, the work done is zero.

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3 years ago

Which type of curved mirror uses its inside as the reflecting surface? A. a convex mirror B. a plane mirror C. a virtual mirror

ser-zykov [4K]

D. a concave mirror

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3 years ago

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