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grandymaker [24]
3 years ago
11

Which two forces operate over the longest distances?

Physics
1 answer:
Harman [31]3 years ago
5 0

Answer:

D Electromagnetic and gravitational

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A potato is launched from the ground at an 73 degree angle with a velocity of 48 m/s.
Wittaler [7]

Answer:

107.4 meters

Explanation:

gravity is 9.8m/s^2

max height = (velocity squared times sin squared angle) ÷ ( speed of gravity times 2 )

max height = (48 squared times sin of 73 squared) ÷ ( 9.8 times 2 )

8 0
2 years ago
g what are the bands of electromagneitc radiation and how are they related to energy frequency and wavelength
ch4aika [34]

Answer:

The details of bands is given in explanation.

Explanation:

The electromagnetic waves are differentiated into different bands based upon their wavelengths and frequencies. The names of different bands are as follows:

1. Radio Waves

2. Micro Waves

3. Infra-red

4. Visible light

5. Ultra Violet

6. X-rays

7. Gamma Rays

<u>The frequency of every region or rays increases from 1 through 7</u>. The <u>energy of rays also increase from 1 through 7</u>. Since, the wave length is inversely related to energy and frequency, thus the <u>wavelength of rays decrease from 1 through 7</u>.

A detailed information of the bands is provided in the picture attached.

3 0
3 years ago
A person on a merry-go-round makes a complete revolution in about 3.17 s.
GREYUIT [131]

Answer:

second one

Explanation:

HOPE THIS helps

8 0
2 years ago
What is the characteristic that allows an object to have kinetic energy?
Shtirlitz [24]
Kinetic energy is movement, thus movement would be a characteristic that allows an object to have kinetic energy
6 0
2 years ago
One of the harmonics on a string 1.30m long has a frequency of 15.60 Hz. The next higher harmonic has a frequency of 23.40 Hz. F
Alja [10]

Answer:

\large \boxed{\text{(a) 7.800 Hz; (b) 20.3 m/s; 40.6 m/s; 60.8 m/s}}

Explanation:

a) Fundamental frequency

A harmonic is an integral multiple of the fundamental frequency.

\dfrac{\text{23.40 Hz}}{\text{15.60 Hz}} = \dfrac{1.500}{1} \approx \dfrac{3}{2}

f = \dfrac{\text{24.30 Hz}}{3} = \textbf{7.800 Hz}

b) Wave speed

(i) Calculate the wavelength

In a  fundamental vibration, the length of the string is half the wavelength.

\begin{array}{rcl}L & = & \dfrac{\lambda}{2}\\\\\text{1.30 m} & = & \dfrac{\lambda}{2}\\\\\lambda & = & \text{2.60 m}\\\end{array}

(b) Calculate the speed s

\begin{array}{rcl}v_{1}& = & f_{1}\lambda\\& = & \text{7.800 s}^{-1} \times \text{2.60 m}\\& = & \textbf{20.3 m/s}\\\end{array}

\begin{array}{rcl}v_{2}& = & f_{2}\lambda\\& = & \text{15.60 s}^{-1} \times \text{2.60 m}\\& = & \textbf{40.6 m/s}\\\end{array}

\begin{array}{rcl}v_{3}& = & f_{3}\lambda\\& = & \text{23.40 s}^{-1} \times \text{2.60 m}\\& = & \textbf{60.8 m/s}\\\end{array}

4 0
3 years ago
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