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Setler [38]
3 years ago
5

With a thunderstorm brewing, an electric field of magnitude 2.0 × 102 newtons/coulomb exists at a certain point in the earth’s a

tmosphere. If an electron at that point has a charge of -1.6 × 10-19 coulombs, what is the magnitude of the force on the electron as a result of the electric field?
A.
2.0 × 10-6 newtons
B.
3.2 × 10-17 newtons
C.
5.8 × 105 newtons
D.
6.4 × 10-3 newtons
E.
1.7 × 104 newtons
Physics
1 answer:
Aleks04 [339]3 years ago
5 0

Answer:

The correct option is (b).

Explanation:

Given that,

Electric field, E=2\times 10^2\ N/C

We need to find the magnitude of the force on the electron as a result of the electric field.

We know that, the electric force is given by :

F=qE\\\\=1.6\times 10^{-19}\times 2\times 10^2\\\\F=3.2\times 10^{-17}\ N

So, the required force on the electron is equal to 3.2\times 10^{-17}\ N.

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A parallel-plate, air-gap capacitor has a capacitance of 0.14 mu F. The plates are 0.5 mm apart, What is the area of each plate?
Marysya12 [62]

Answer:

7.9060 m²

8.57 Volts

5.142×10⁻⁶ Joule

1.2×10⁻⁶ Coulomb

Explanation:

C = Capacitance between plates = 0.14 μF = 0.14×10⁻⁶ F

d = Distance between plates = 0.5 mm = 0.5×10⁻³ m

Q = Charge = 1.2 μC = 1.2×10⁻⁶ C

ε₀ = Permittivity = 8.854×10⁻¹² F/m

Capacitance

C=\frac{\epsilon_{0}A}{d}\\\Rightarrow A=\frac{Cd}{\epsilon_{0}}\\\Rightarrow A=\frac{0.14\times 10^{-6}\times 0.5\times 10^{-3}}{8.854\times 10^{-12}}\\\Rightarrow A=7.9060\ m^2

∴ Area of each plate is 7.9060 m²

Voltage

V=\frac{Q}{C}\\\Rightarrow V=\frac{1.2\times 10^{-6}}{0.14\times 10^{-6}}\\\Rightarrow V=8.57\ Volts

∴ Potential difference between the plates if the capacitor is charged to 1.2 μC  is 8.57 Volts.

Energy stored

E=0.5CV²

⇒E = 0.5×0.14×10⁻⁶×8.57²

⇒E = 5.142×10⁻⁶ Joule

∴ Stored energy is 5.142×10⁻⁶ Joule

Charge

Q = CV

⇒Q = 0.14×10⁻⁶×8.57

⇒Q = 1.2×10⁻⁶ C

∴ Charge the capacitor carries before a spark occurs between the two plates is 1.2×10⁻⁶ Coulomb

6 0
3 years ago
¿Qué es la velocidad?
egoroff_w [7]

Velocidad-es una cantidad vectorial física; Tanto la magnitud como la dirección son necesarias para definirlo.

5 0
3 years ago
Aluminum oxide can be produced during rocket launches. Show that the sum of positive and negative charges in a unit of Al2O3 equ
Triss [41]

Answer:

The sum of positive and negative charges in a unit of Al2O3 equals zero.

Aluminium has a charge of +3 while Oxygen has a charge of -2 on each ion.

Al203 has 2 Al atoms and 3 O atoms.

Charge on Al2O3 = 2(charge on Al ion) + 3(charge on O ion)

= 2(3) + 3(-2)

= 6 - 6

= 0

Explanation:

Aluminium has 3 electrons in the outermost shell and has the tendency to lose those 3 electrons to form a positive ion and have a complete outermost shell.

Whereas, Oxygen has 6 electrons in the outermost and has the tendency to accept two more electrons to form a negative ion and have a complete outermost shell.

4 0
3 years ago
A radio station broadcast on a frequency of 3.7 mhz what is the energy of the radio wave
Ratling [72]

A radio station broadcast on a frequency of 3.7 mhz what is the energy of the radio wave A radio station broadcasts its programmes at a wavelength of 500 m. Find the frequency of the radiowaves transmitted by the radio station, if the speed of radiowaves in air is 3 x 108 m/s. Ans: 6 x 10 Hz

<h3>What is radio station ?</h3>

Radio broadcasting is the act of sending audio (sound), occasionally together with accompanying metadata, across radio waves to radio receivers used by the general public. Unlike satellite radio, which uses a satellite in Earth's orbit, terrestrial radio broadcasting uses a land-based radio station to transmit radio waves. The listener needs a broadcast radio receiver to hear the material (radio). A radio network with which stations frequently have affiliations provide content in a standard radio format, whether through broadcast syndication, simulcasting, or both. Radio stations use a variety of modulations to transmit their signals, including FM (frequency modulation), which is an older analog audio standard, and AM (amplitude modulation).

To learn more about radio station from the given link:

brainly.com/question/26439029

#SPJ4

3 0
2 years ago
If measurements of gas are 75 L and 300 kIlopascals and then the gas is measured is second time and found to be 50 L, describe w
Ann [662]

Answer:

The pressure must have increased in the process

Explanation:

The State Equation for gasses reads: P*V=n*R*T

where P is the gas' pressure, V its volume, n the number of moles of gas,  R the gas constant and T the temperature in degrees Kelvin.

If the temperature of the gas doesn't change in the described process, the right hand side of the equation stays the same. If that is the case, given that when the Volume of the gas diminishes from 75 liters to 50 liters, then the pressure must have increased to keep that product "P * V" constant:

P_i*V_i=P_f*V_f\\75 *300=50*X\\X=\frac{75*300}{50} =450

So the pressure must have gone up to 450 kilopascals.

3 0
3 years ago
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