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vladimir2022 [97]
3 years ago
12

If a person traveled from Sacramento to Los Angeles by car, their distance would be 384.9 miles. What would their displacement b

e? _____________________ If that same person returned to Sacramento from Los Angeles by the same route in the same car, what would the total round trip distance be? 400 miles What would their total displacement be? _____________________
Physics
1 answer:
kumpel [21]3 years ago
3 0

Answer:

Displacement from Sacramento to Los Angeles is 384.9 miles

Total path length is given as 769.8 miles

Displacement of complete round trip is ZERO

Explanation:

As we know that the displacement is the change in the position from initial to final in a straight line

Here we know that the car travel from Sacramento to Los Angeles

So the straight line distance between two is the displacement

so we have

displacement = 384.9 miles

Now we know that he returns from Los Angeles to Sacramento by same path

So total distance moved by it is same as total path length

d = 384.9 + 384.9

d = 769.8 miles

Also we know that initial and final positions are same so displacement is ZERO for complete round trip.

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seraphim [82]

C

Explanation:

that's just what I learned in school

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3 years ago
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Using Rayleigh's criterion, calculate the diameter of an earth-based telescope that gives this resolution with 700 nm light.
pogonyaev

Complete Question

Due to blurring caused by atmospheric distortion, the best resolution that can be obtained by a normal, earth-based, visible-light telescope is about 0.3 arcsecond (there are 60 arcminutes in a degree and 60 arcseconds in an arcminute).Using Rayleigh's criterion, calculate the diameter of an earth-based telescope that gives this resolution with 700 nm light

Answer:

The diameter is  D = 0.59 \  m    

Explanation:

From the question we are told that

      The best resolution is  \theta  =  0.3 \  arcsecond

       The  wavelength is  \lambda  =  700 \  nm =  700 *10^{-9 } \  m

       

Generally the

         1 arcminute  = >  60 arcseconds

=>      x arcminute =>   0.3 arcsecond

So

       x =  \frac{0.3}{60 }

=>    x = 0.005 \  arcminutes

Now

         60 arcminutes  =>  1 degree

          0.005 arcminutes = >  z degrees  

=>       z =  \frac{0.005}{60 }

=>      z =  8.333 *10^{-5}  \ degree

Converting to radian  

           \theta  = z =  8.333 *10^{-5}  * 0.01745 = 1.454 *10^{-6} \  radian

Generally the resolution is mathematically represented as

            \theta  =  \frac{1.22 *  \lambda  }{ D}

=>    D =  \frac{1.22 * \lambda }{\theta }

=>     D =  \frac{1.22 * 700 *10^{-9} }{ 1.454 *10^{-6} }    

=>     D = 0.59 \  m    

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Nana76 [90]
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So u see what had happened was i need help again..
liubo4ka [24]

first off lemme just say this is really easy man, just look at the directions

Blank #1: -23

Blank #2: 23

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