No because the exponent on 6^3 is 216 and if you use (4•6)^3 then you’ll have to multiply the quotations and then Square it to the third
Standard form of a circle" (x-h)²+(y-k)²=r², (h,k) being the center, r being the radius.
in this case, h=-2, k=6, (x+2)²+(y-6)²=r²
use the point (-2,10) to find r: (-2+2)²+(10-6)²=r², r=4
so the equation of the circle is: (x+2)²+(y-6)²=4²
Answer:
(0, -1)
Step-by-step explanation:
x becomes x - 6, so subtract 6 from the x-coordinate.
y becomes y - 1, so subtract 1 from the y-coordinate.
P(6, 0) -----> P'(0, -1)
Answer:
It is a line with a positive slope and positive intercept
Step-by-step explanation:
If you want it in SF, -x + y = 4
Answer:
(1, 2)
Step-by-step explanation:
Given the equation of the lines x + 2y = 5 and 2x - 3y = -4
First we need to make x the subject of the formulas
For x+2y = 5
x = 5 - 2y ... 1
For 2x - 3y = -4
2x = -4+3y
x = (-4+3y)/2 ... 2
Equate 1 and 2
5 - 2y = (-4+3y)/2
2(5-2y) = -4+3y
10 - 4y = -4+3y
-4 -3y = -4-10
-7y = -14
y = 14/7
y = 2
Substitute y = 2 into 1
x = 5 = 2y
x = 5 - 2(2)
x = 5 - 4
x = 1
Hence the point where the lines meet will be at (1, 2)
