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3 years ago

8

Suggest five questions for a questionnaire to discover what opinions people in class have about school.

1 answer:

Snezhnost [94]3 years ago

8 0

Answer:

Which activities in the classroom do you enjoy the most? ...

Given a chance, what is one change that you would like to see? ...

Do you have supportive classmates? ...

What motivates you to learn more? ...

Do you think that the school provides you with adequate sports facilities?

How much time do you spend on homework every night?

Which classroom activities do you learn from the most?

What are three things that can improve the class most?

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Which number is in the solution set of the inequality -5x - 7 > 28?

Vanyuwa [196]

Answer:

x>-7

Step-by-step explanation:

A

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2 years ago

Find the area of a triangle with an 11-inch base and a 6-inch height.<br> A =

maksim [4K]

Area=1/2 times base times height

given
base=11in
height=6in

area=1/2 times 11 times 6
area=66/2 square inches
area=33 square inches

the area is 33 in²

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3 years ago

PLEASE HELP ME I DONT UNDERSTAND

miss Akunina [59]

Answer:

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Step-by-step explanation:

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3 years ago

Change each of the following points from rectangular coordinates to spherical coordinates and to cylindrical coordinates.

FromTheMoon [43]

Answer and Step-by-step explanation: Spherical coordinate describes a location of a point in space: one distance (ρ) and two angles (Ф,θ).To transform cartesian coordinates into spherical coordinates:

$\rho = \sqrt{x^{2}+y^{2}+z^{2}}$

$\phi = cos^{-1}\frac{z}{\rho}$

For angle θ:

If x > 0 and y > 0: $\theta = tan^{-1}\frac{y}{x}$ ;

If x < 0: $\theta = \pi + tan^{-1}\frac{y}{x}$ ;
If x > 0 and y < 0: $\theta = 2\pi + tan^{-1}\frac{y}{x}$ ;

Calculating:

a) (4,2,-4)

$\rho = \sqrt{4^{2}+2^{2}+(-4)^{2}}$ = 6

$\phi = cos^{-1}(\frac{-4}{6})$

$\phi = cos^{-1}(\frac{-2}{3})$

For θ, choose 1st option:

$\theta = tan^{-1}(\frac{2}{4})$

$\theta = tan^{-1}(\frac{1}{2})$

b) (0,8,15)

$\rho = \sqrt{0^{2}+8^{2}+(15)^{2}}$ = 17

$\phi = cos^{-1}(\frac{15}{17})$

$\theta = tan^{-1}\frac{y}{x}$

The angle θ gives a tangent that doesn't exist. Analysing table of sine, cosine and tangent: θ = $\frac{\pi}{2}$

c) (√2,1,1)

$\rho = \sqrt{(\sqrt{2} )^{2}+1^{2}+1^{2}}$ = 2

$\phi = cos^{-1}(\frac{1}{2})$

$\phi$ = $\frac{\pi}{3}$

$\theta = tan^{-1}\frac{1}{\sqrt{2} }$

d) (−2√3,−2,3)

$\rho = \sqrt{(-2\sqrt{3} )^{2}+(-2)^{2}+3^{2}}$ = 5

$\phi = cos^{-1}(\frac{3}{5})$

Since x < 0, use 2nd option:

$\theta = \pi + tan^{-1}\frac{1}{\sqrt{3} }$

$\theta = \pi + \frac{\pi}{6}$

$\theta = \frac{7\pi}{6}$

Cilindrical coordinate describes a 3 dimension space: 2 distances (r and z) and 1 angle (θ). To express cartesian coordinates into cilindrical:

$r=\sqrt{x^{2}+y^{2}}$

Angle θ is the same as spherical coordinate;

z = z

Calculating:

a) (4,2,-4)

$r=\sqrt{4^{2}+2^{2}}$ = $\sqrt{20}$

$\theta = tan^{-1}\frac{1}{2}$

z = -4

b) (0, 8, 15)

$r=\sqrt{0^{2}+8^{2}}$ = 8

$\theta = \frac{\pi}{2}$

z = 15

c) (√2,1,1)

$r=\sqrt{(\sqrt{2} )^{2}+1^{2}}$ = $\sqrt{3}$

$\theta = \frac{\pi}{3}$

z = 1

d) (−2√3,−2,3)

$r=\sqrt{(-2\sqrt{3} )^{2}+(-2)^{2}}$ = 4

$\theta = \frac{7\pi}{6}$

z = 3

5 0

3 years ago

A rectangular sheet of paper is 25/2cm long and 32/3 cm wide. Find its perimeter. *

Zina [86]

Answer:

46.3cm

Step-by-step explanation:

perimeter is length around shape
25/2 multiply by 2 becoz it's got two equal sides
32/3 multiply by two for the other equal sides
add answers together to give you
46.3cm

3 0

3 years ago

Read 2 more answers