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2 years ago

Graph y < 1 -3x. Plz help me I will give branilest

Mathematics

1 answer:

Marianna [84]2 years ago

5 0

Answer: Someone tell me if i'm wrong but from this I think it might be the fourth one (?)

Step-by-step explanation:

y=1

A straight line in slope (m) and intercept (c) form is:y=mx +c

In this example, y is a straight line of slope 0 and y −intercept of 1 ∴ y =0⋅

x+1

Hence, the graph of y a is straight line parallel to the x −axis through the point

(0,1)

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Please help me with this

zhannawk [14.2K]

I’m pretty sure it’s 82

6 0

3 years ago

Plzzz HELP will give brainliest 9^-53*9^37

slamgirl [31]

Answer: The exact form is 5.3965953e-16. But in exponential form: 9^(-16).

Step-by-step explanation:

Use your calculator to plug in the negative powers and to multiply. Do it one step at a time. If you want exponential form, then here:

9^(-53) * 9^(37)

Add exponents keep base

9^(-16)

Hope this helps

3 0

3 years ago

Which graph represents the solution set of the compound inequality -43x-1 and 2x+43 18?

r-ruslan [8.4K]

Answer:

Step-by-step explanation:

YOU CAN DO THIS :)

7 0

2 years ago

Solve the initial value problem where y′′+4y′−21 y=0, y(1)=1, y′(1)=0 . Use t as the independent variable.

igor_vitrenko [27]

Answer:

$y = \frac{7}{10} e^{3(t - 1)} + \frac{3}{10}e^{-7(t - 1)}$

Step-by-step explanation:

y′′ + 4y′ − 21y = 0

The auxiliary equation is given by

m² + 4m - 21 = 0

We solve this using the quadratic formula. So

$m = \frac{-4 +/- \sqrt{4^{2} - 4 X 1 X (-21))} }{2 X 1}\\ = \frac{-4 +/- \sqrt{16 + 84} }{2}\\= \frac{-4 +/- \sqrt{100} }{2}\\= \frac{-4 +/- 10 }{2}\\= -2 +/- 5\\= -2 + 5 or -2 -5\\= 3 or -7$

So, the solution of the equation is

$y = Ae^{m_{1} t} + Be^{m_{2} t}$

where m₁ = 3 and m₂ = -7.

So,

$y = Ae^{3t} + Be^{-7t}$

Also,

$y' = 3Ae^{3t} - 7e^{-7t}$

Since y(1) = 1 and y'(1) = 0, we substitute them into the equations above. So,

$y(1) = Ae^{3X1} + Be^{-7X1}\\1 = Ae^{3} + Be^{-7}\\Ae^{3} + Be^{-7} = 1 (1)$

$y'(1) = 3Ae^{3X1} - 7Be^{-7X1}\\0 = 3Ae^{3} - 7Be^{-7}\\3Ae^{3} - 7Be^{-7} = 0 \\3Ae^{3} = 7Be^{-7}\\A = \frac{7}{3} Be^{-10}$

Substituting A into (1) above, we have

$\frac{7}{3}B e^{-10}e^{3} + Be^{-7} = 1 \\\frac{7}{3}B e^{-7} + Be^{-7} = 1\\\frac{10}{3}B e^{-7} = 1\\B = \frac{3}{10} e^{7}$

Substituting B into A, we have

$A = \frac{7}{3} \frac{3}{10} e^{7}e^{-10}\\A = \frac{7}{10} e^{-3}$

Substituting A and B into y, we have

$y = Ae^{3t} + Be^{-7t}\\y = \frac{7}{10} e^{-3}e^{3t} + \frac{3}{10} e^{7}e^{-7t}\\y = \frac{7}{10} e^{3(t - 1)} + \frac{3}{10}e^{-7(t - 1)}$

So the solution to the differential equation is

$y = \frac{7}{10} e^{3(t - 1)} + \frac{3}{10}e^{-7(t - 1)}$

6 0

4 years ago

Which of the following is the function F(x) if F^-1(x) = x+4/11?

Marianna [84]

Answer:

B. F(x) =X-4/11

Step-by-step explanation:

We are given the inverse function;

f^(-1)(x) = x + 4/11

Thus means, x was replaced with y and vise versa. Thus;

x = y + 4/11

Lets make y the subject;

y = x - 4/11

Thus,in inverse of a function we replace y with f(x) for the original function or f^(1)(x) for the inverse.

Thus, putting f(x) for y gives;

f(x) = x - 4/11

8 0

3 years ago