Question

I need help with these 3 questions. No links, please.

Answer 1

Answer:

Q9: C.

Since each smaller line counts as 1/5, you can simply start from the point 1 and count 3 times to reach D.

$3*\frac{1}{5} =\frac{3}{5}$

Since you started at 1, you can add $1+\frac{3}{5} =1\frac{3}{5}$

Q10: B

We can subtract/ignore 3 from all of them to make things simpler.

Now, we need to find the lowest value to greatest from:

$\frac{5}{8}, \frac{7}{16} ,\frac{1}{2}$

In order to compare these, we make the denominators the same (in this case: 16)

$\frac{5}{8} =\frac{5*2}{8*2} =\frac{10}{16}$

$\frac{7}{16} =\frac{7}{16}$

$\frac{1}{2} =\frac{1*8}{2*8} =\frac{8}{16}$

Since 7 is the smallest value, followed by 8 and lastly 10,

the smallest to greatest in order would be

$\frac{7}{16} ,\frac{1}{2} ,\frac{5}{8}$ (B)

11: C

If you look at both $\frac{2}{4}$ and $\frac{5}{8}$, they are not directly above one another. Hence, they are not equal.