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shepuryov [24]
2 years ago
13

Plz help I need help

Mathematics
2 answers:
Simora [160]2 years ago
6 0

Answer:

a. 1/4

Step-by-step explanation:

no need for explanation

its basic

pantera1 [17]2 years ago
3 0

Answer:

7/21

Step-by-step explanation:

14/42

Divide the top and bottom by 7

14/7 =2

42/7 = 6

2/6 = 1/3

We need a ratio that is 1/3

7/21

Divide by 7

1/3

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last year a football game scored a total of 427 points, so far this year, they have scored 154 points. They have eight more regu
vfiekz [6]

Answer:

35 points

Step-by-step explanation:

See photo

6 0
3 years ago
Can someone plz help me with this one problem plz!!!
maksim [4K]

answer is d or c because when u find Mean u add all numbers the. divide and median is middle number

Step-by-step explanation:

mean us 7.5 median is 6 asssss

7 0
3 years ago
What do I do to solve this
Nimfa-mama [501]
A smoke and a pancake?
8 0
3 years ago
The function f(x)=Acosh(Cx)+Bsinh(Cx). I need help determining the value of constant C>0 when the second derivative f''(x)=25
Rus_ich [418]

Answer:

C = 5.

Step-by-step explanation:

First, you need to remember that:

For the function:

h(x) = Sinh(k*x)

We have:

h'(x) = k*Cosh(k*x)

and for the Cosh function:

g(x) = Cosh(k*x)

g'(x) = k*Cosh(k*x).

Now let's go to our problem:

We have f(x) = A*cosh(C*x) + B*Sinh(C*x)

We want to find the value of C such that:

f''(x) = 25*f(x)

So let's derive f(x):

f'(x) = A*C*Sinh(C*x) + B*C*Cosh(C*x)

and again:

f''(x) = A*C*C*Cosh(C*x) + B*C*C*Sinh(C*x)

f''(x) = C^2*(A*cosh(C*x) + B*Sinh(C*x)) = C^2*f(x)

And we wanted to get:

f''(x) = 25*f(x) = C^2*f(x)

then:

25 = C^2

√25 = C

And because we know that C > 0, we take the positive solution of the square root, then:

C = 5

6 0
2 years ago
Please help. Write the equation of the graph. (Do not use spaces. Use ^ to represent exponents. Example 2^3 is 23.)
lana66690 [7]
This graph has a horizontal asymptote so it is an exponential graph. It also passes through two points (0,-2) and (1,3). The horizontal asymptote is at y=-3.
The unchanged exponential equation is y=a(b)^x +k
For exponential equations, k is always equal to the horizontal asymptote, so k=-3.
You can check this with the ordered pair (0,-2). After that plug in the other ordered pair, (1,3).
This gives you 3=a(b)^1 or 3=ab. If you know the base the answer is simple as you just solve for a.
If you don't know the base at this point you have to sort of guess. For example, let's say both a and b are whole numbers. In that case b would have to be 3, as it can't be 1 since then the answer never changes, and a is 1. Then choose an x-value and not exact corresponding y-value. In this case x=-1 and y= a bit less than -2.75. Plug in the values to your "final" equation of y=(3)^x -3.
So -2.75=(3^-1)-3. 
3^-1 is 1/3, 1/3-3 is -8/3 or -2.6667 which is pretty close to -2.75. So we can say the final equation is y=3^x -3. 
Hope this helps! It's a lot easier to solve problems like these given either more points which you can use system of equations with, or with a given base or slope. 
7 0
3 years ago
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