The forces exerted on an object are shown.

A man hits a golf ball (0.2 kg) which accelerates at a rate of 20 m/s2. What amount of force acted on the ball?

Delvig [45]

Newton taught us that Force = (mass) x (acceleration)

Force = (0.2) x (20) = <em>4 newtons</em> .

Something to think about: The ball can only accelerate while the club-face
is in contact with it. Once the ball leaves the club, it can't accelerate any more,
because the force against it is gone.

4 0

3 years ago

To find some of the parameters characterizing an object moving in a circular orbit.The motivation for Isaac Newton to discover h

tamaranim1 [39]

Answer:

$K = \frac{GMm}{2r}$

$T^2 = 4\pi^2(\frac{r^3}{GM})$

Explanation:

As we know that for a satellite the force of gravitation is equal to the centripetal force

so we will have

$F = \frac{GMm}{r^2}$

$\frac{mv^2}{r} = \frac{GMm}{r^2}$

so we know that kinetic energy is given as

$K = \frac{1}{2}mv^2$

so we have

$K = \frac{GMm}{2r}$

now for time period we know

$T = \frac{2\pi r}{v}$

from above expression of kinetic energy we have

$v = \sqrt{\frac{GM}{r}}$

so we have

$T = \frac{2\pi r}{\sqrt{\frac{GM}{r}}}$

so square of time period is given as

$T^2 = 4\pi^2(\frac{r^3}{GM})$

3 0

3 years ago

Earth's three main climate zones are a result of unequal heating caused by differences in

andreev551 [17]

B. Longitude I think

8 0

3 years ago

Read 2 more answers

A 0.300kg glider is moving to the right on a frictionless, horizontal air track with a speed of 0.800m/s when it makes a head-o

e-lub [12.9K]

Answer:

The final velocity of the first glider is 0.27 m/s in the same direction as the first glider

The final velocity of the second glider is 1.07 m/s in the same direction as the first glider.

0.010935 J

0.0858675 J

Explanation:

$m_1$ = Mass of first glider = 0.3 kg

$m_2$ = Mass of second glider = 0.15 kg

$u_1$ = Initial Velocity of first glider = 0.8 m/s

$u_2$ = Initial Velocity of second glider = 0 m/s

$v_1$ = Final Velocity of first glider

$v_2$ = Final Velocity of second glider

As momentum and Energy is conserved

$m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}$

${\tfrac {1}{2}}m_{1}u_{1}^{2}+{\tfrac {1}{2}}m_{2}u_{2}^{2}={\tfrac {1}{2}}m_{1}v_{1}^{2}+{\tfrac {1}{2}}m_{2}v_{2}^{2}$

From the two equations we get

$v_{1}=\frac{m_1-m_2}{m_1+m_2}u_{1}+\frac{2m_2}{m_1+m_2}u_2\\\Rightarrow v_1=\frac{0.3-0.15}{0.3+0.15}\times 0.8+\frac{2\times 0.15}{0.3+0.15}\times 0\\\Rightarrow v_1=0.27\ m/s$

The final velocity of the first glider is 0.27 m/s in the same direction as the first glider

$v_{2}=\frac{2m_1}{m_1+m_2}u_{1}+\frac{m_2-m_1}{m_1+m_2}u_2\\\Rightarrow v_2=\frac{2\times 0.3}{0.3+0.15}\times 0.8+\frac{0.3-0.15}{0.3+0.15}\times 0\\\Rightarrow v_2=1.067\ m/s$

The final velocity of the second glider is 1.07 m/s in the same direction as the first glider.

Kinetic energy is given by

$K=\frac{1}{2}m_1v_1^2\\\Rightarrow K=\frac{1}{2}0.3\times 0.27^2\\\Rightarrow K=0.010935\ J$

Final kinetic energy of first glider is 0.010935 J

$K=\frac{1}{2}m_2v_2^2\\\Rightarrow K=\frac{1}{2}0.15\times 1.07^2\\\Rightarrow K=0.0858675\ J$

Final kinetic energy of second glider is 0.0858675 J

6 0

3 years ago

What does it mean for the forces acting on an object to be balanced?

Savatey [412]

When the forces are said to be balance, it means that net force is zero.

<h3>What is Net force?</h3>

When two or more forces are acting on the system of objects, then the to attain equilibrium, net force must be zero.

The resultant of all the forces in horizontal and vertical direction is zero, when the forces are balanced.

Learn more about net force.

brainly.com/question/18031889

#SPJ1

3 0

2 years ago