Two observers in different inertial reference frames moving relative to each other at nearly the speed of light see the same two
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Convert 38 ft/s^2 to mi/h^2. Then we se the conversion factor > 1 mile = 5280 feet and 1 hour = 3600 seconds.
So now we show it >
Then we have to use the formula of constant acceleration to determine the distance traveled by the car before it ended up stopping.
Which the formula for constant acceleration would be >
The initial velocity is 50mi/h
When it stops the final velocity is
Since the given is deceleration it means the number we had gotten earlier would be a negative so a = -93272.27
Then we substitute the values in....
So we can say the car stopped at 0.0134 miles before it came to a stop but to express the distance traveled in feet we need to use the conversion factor of 1 mile = 5280 feet in otherwards >
So this means that the car traveled in feet 70.8 ft before it came to a stop.
There you go.
Hope this helps!
Hope this helps!