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Pani-rosa [81]
3 years ago
14

Two observers in different inertial reference frames moving relative to each other at nearly the speed of light see the same two

events but, using precise equipment, record different time intervals between the two events. Which of the following is true of their measurements?
(a)One observer is incorrect, but it is impossible to tell which one.
(b)One observer is incorrect, and it is possible to tell which one.
(c)Both observers are incorrect.
(d)Both observers are correct.
Physics
1 answer:
lions [1.4K]3 years ago
3 0

Answer:

The correct answer is d Both the observer's are correct

Explanation:

We know by postulates of relativity that laws of physics are same in different inertial frames.

Thus for each of the frames they make observations related to their frames and since the observations are true for their individual frames they both are correct. But when we compare the two frames we need to use transformation equations to compare both the results.

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The intensity of light from a star (its brightness) is the power it outputs divided by the surface area over which it’s spread:
kow [346]

Answer:

\frac{d_{1}}{d_{2}}=0.36

Explanation:

1. We can find the temperature of each star using the Wien's Law. This law is given by:

\lambda_{max}=\frac{b}{T}=\frac{2.9x10^{-3}[mK]}{T[K]} (1)

So, the temperature of the first and the second star will be:

T_{1}=3866.7 K

T_{2}=6444.4 K

Now the relation between the absolute luminosity and apparent brightness  is given:

L=l\cdot 4\pi r^{2} (2)

Where:

  • L is the absolute luminosity
  • l is the apparent brightness
  • r is the distance from us in light years

Now, we know that two stars have the same apparent brightness, in other words l₁ = l₂

If we use the equation (2) we have:

\frac{L_{1}}{4\pi r_{1}^2}=\frac{L_{2}}{4\pi r_{2}^2}

So the relative distance between both stars will be:

\left(\frac{d_{1}}{d_{2}}\right)^{2}=\frac{L_{1}}{L_{2}} (3)

The Boltzmann Law says, L=A\sigma T^{4} (4)

  • σ is the Boltzmann constant
  • A is the area
  • T is the temperature
  • L is the absolute luminosity

Let's put (4) in (3) for each star.

\left(\frac{d_{1}}{d_{2}}\right)^{2}=\frac{A_{1}\sigma T_{1}^{4}}{A_{2}\sigma T_{2}^{4}}

As we know both stars have the same size we can canceled out the areas.

\left(\frac{d_{1}}{d_{2}}\right)^{2}=\frac{T_{1}^{4}}{T_{2}^{4}}

\frac{d_{1}}{d_{2}}=\sqrt{\frac{T_{1}^{4}}{T_{2}^{4}}}

\frac{d_{1}}{d_{2}}=\sqrt{\frac{T_{1}^{4}}{T_{2}^{4}}}

\frac{d_{1}}{d_{2}}=0.36

I hope it helps!

5 0
3 years ago
Heavy water usually refers to water that : (A) has been frozen, and so is more dense (B) has had its hydrogen removed (C) is rad
Roman55 [17]

Answer:

Option (D)

Explanation:

The chemical formula for normal water is H2O and the chemical formula for heavy water is D2O.

Where D is deuterium which is the isotope of hydrogen.

There are three isotopes of hydrogen.

1H1 it is called protium.

1H2 it is called deuterium.

1H3 it is called tritium.

6 0
3 years ago
Read 2 more answers
What is the relationship between mass, volume, and density? What is the relationship between mass, volume, and density? Density
kirza4 [7]

Answer:

A. Density is proportional to mass and inversely proportional to volume

Explanation:

Density can be defined as the property that matter has, whether solids, liquids or gases, to be compressed in a given space.

The expression that relates the density with the another values is given by,

\rho= \frac{m}{V}

Where,

\rho \propto m  (It is directly proportional to the mass of the object)

\rho = \frac{1}{V}(It is inversely proportional to the volumen of the object)

<em>Therefore density is directly proportional to the mass and inversely proportional to the volumen.</em>

4 0
3 years ago
When scientists publish experimental results their results are often criticized by other scientists how is this process a source
stiv31 [10]

Answer: It encourages scientists to give convincing evidence for the results

5 0
3 years ago
The first energy level holds how many electrons?
Mama L [17]

Answer: two electrons

Explanation:  The first principal energy level contains only an s sublevel; therefore, it can hold a maximum of two electrons. Each principal energy level above the first contains one s orbital and three p orbitals. A set of three p orbitals, called the p sublevel, can hold a maximum of six electrons.

4 0
3 years ago
Read 2 more answers
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