1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Pani-rosa [81]
3 years ago
14

Two observers in different inertial reference frames moving relative to each other at nearly the speed of light see the same two

events but, using precise equipment, record different time intervals between the two events. Which of the following is true of their measurements?
(a)One observer is incorrect, but it is impossible to tell which one.
(b)One observer is incorrect, and it is possible to tell which one.
(c)Both observers are incorrect.
(d)Both observers are correct.
Physics
1 answer:
lions [1.4K]3 years ago
3 0

Answer:

The correct answer is d Both the observer's are correct

Explanation:

We know by postulates of relativity that laws of physics are same in different inertial frames.

Thus for each of the frames they make observations related to their frames and since the observations are true for their individual frames they both are correct. But when we compare the two frames we need to use transformation equations to compare both the results.

You might be interested in
A uniform plane wave traveling in air is incident upon a flat, lossless, and infinite in extent dielectric interface with a diel
dexar [7]

Answer:

Check the explanation

Explanation:

Kindly check the attached images below to see the step by step explanation to the question above.

3 0
2 years ago
In facts about Plastics, Explorer how the economy (the way materials are made, sold, and bought) is affected by using and produc
Mandarinka [93]

Producing plastics benefits the economy by employing workers and helps the economy of every state by spending billions of dollars on shipping plastic products.

4 0
3 years ago
Read 2 more answers
A toy train is pushed forward and released at Xi = 4.0 m with a speed of 2.5 m/s. It rolls at a steady speed for 2.0 s, then one
Fittoniya [83]
I don't think that 4m has anything to do with the problem. anyway. here. A___________________B_______C where A is the point that the train was released. B is where the wheel started to stick C is where it stopped From A to B, v=2.5m/s, it takes 2s to go A to B so t=2 AB= v*t = 2.5 * 2 = 5m The train comes to a stop 7.7 m from the point at which it was released so AC=7.7m then BC= AC-AB = 7.7-5 = 2.7m now consider BC v^2=u^2+2as where u is initial speed, in this case is 2.5m/s v is final speed, train stop at C so final speed=0, so v=0 a is acceleration s is displacement, which is BC=2.7m substitute all the number into equation, we have 0^2 = 2.5^2 + 2*a*2.7 0 = 6.25 + 5.4a a = -6.25/5.4 = -1.157 so acceleration is -1.157m/(s^2)
8 0
3 years ago
Read 2 more answers
A packing crate rests on a horizontal surface. It is acted on by three horizontal forces: 600 N to the left, 200 N to the right,
egoroff_w [7]

Answer:

The resultant force would (still) be zero.

Explanation:

Before the 600-N force is removed, the crate is not moving (relative to the surface.) Its velocity would be zero. Since its velocity isn't changing, its acceleration would also be zero.

In effect, the 600-N force to the left and 200-N force to the right combines and acts like a 400-N force to the left.

By Newton's Second Law, the resultant force on the crate would be zero. As a result, friction (the only other horizontal force on the crate) should balance that 400-N force. In this case, the friction should act in the opposite direction with a size of 400 N.

When the 600-N force is removed, there would only be two horizontal forces on the crate: the 200-N force to the right, and friction. The maximum friction possible must be at least 200 N such that the resultant force would still be zero. In this case, the static friction coefficient isn't known. As a result, it won't be possible to find the exact value of the maximum friction on the crate.

However, recall that before the 600-N force is removed, the friction on the crate is 400 N. The normal force on the crate (which is in the vertical direction) did not change. As a result, one can hence be assured that the maximum friction would be at least 400 N. That's sufficient for balancing the 200-N force to the right. Hence, the resultant force on the crate would still be zero, and the crate won't move.

6 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Natasha_Volkova [10]

Ok srry bout last time but the answer is A) kelvin: time the reason is because everything else is a SI. Hope this helps and TURTLE

7 0
3 years ago
Read 2 more answers
Other questions:
  • A snowball is rolling down a hill at 4.5 m/s and accumulating snow as it goes. Its diameter begins at 0.50 m and ends at the bot
    11·1 answer
  • The force on a wire is a maximum of6.71 10-2 N when placed between the pole faces of a magnet.The current flows horizontally to
    7·1 answer
  • A 0.020-kg bullet traveling at a speed of 300 m/s embeds in a 1.0-kg wooden block resting on a horizontal surface. The block sli
    14·1 answer
  • Denise is riding her bike and falls to the ground. During the collision, she hits both grass and cement.
    5·1 answer
  • In the early 19th century Christian Doppler, an Austrian physicist, proposed a theory regarding the properties of a moving sourc
    8·1 answer
  • Find change of velocity for:<br> 0-1.7 s<br> 1.7-6s
    8·1 answer
  • Where do scientists believe the missing carbon is going? Why are they not sure?
    5·1 answer
  • A bat strikes a 0.145-kg baseball. Just before impact, the ball is traveling horizontally to the right at 60.0 m/s , and it leav
    13·1 answer
  • Hi, I'm stuck on the problem: Consider a resistor (R=1000 kΩ) and a capacitor (C=1μF) connected in series. This configuration is
    15·1 answer
  • How do i make someone like me before they talk to me
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!