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2 years ago

Research has shown ____ often depends on one's current status, circumstances, and expectations.

Physics

1 answer:

larisa86 [58]2 years ago

6 0

Answer:

A. subjective well-being

Explanation:

A subjective well being does indeed often on the status, expectations and circumstances according to the theory of emotion. Also, there are flashcards on quizlet about this subject so if you want to learn more go there!

You might be interested in

A student in Denver (altitude = 1 mile = 1609 m above sea level) brings a physics book of mass 1.3 kg to the top of a ten story

Nesterboy [21]

Answer:

Explanation:

Potential energy is the energy of a body due to is virtue of rest.

Potential energy is given as mgh

g is a constant and it is 9.81m/s²

And also the mass of the body is given as 1.3kg

Now the height of the body is

He took a book to a storey building of height 26m

He still holds the book 151 cm (1.51m) above the house.

The house is on an altitude of 1609m from the sea level.

Total Ug with out the sea level is

Ug=mgh

Ug=1.3 × 9.81 ×(26+1.51)

Ug=350.84J

Then, the potential energy due to the sea level is given as

Ug=mgh

Where g = 1/6371 m/s²

Therefore

Ug=mgh

Ug=1.3 × 1/6371 ×1609

Ug=0.328J

Total energy = 0.328+350.84

Ug=351.17J

8 0

3 years ago

A 40-cmcm-long tube has a 40-cmcm-long insert that can be pulled in and out. A vibrating tuning fork is held next to the tube. A

Licemer1 [7]

Answer:

1070 Hz

Explanation:

First, I should point out there might be a typo in the question or the question has inconsistent values. If the tube is 40 cm long, standing waves cannot be produced at 42.5 cm and 58.5 cm lengths. I assume the length is more than the value in the question then. Under this assumption, we proceed as below:

The insert in the tube creates a closed pipe with one end open and the other closed. For a closed pipe, the difference between successive resonances is a half wavelength $\frac{\lambda}{2}$ .

Hence, we have

$\dfrac{\lambda}{2}=58.5-42.5=16 \text{ cm}$

$\lambda=32\text{ cm}=0.32 \text{ m}$ .

The speed of a wave is the product of its wavelength and its frequency.

$v=f\lambda$

$f=\dfrac{v}{\lambda}$

$f=\dfrac{343}{0.32}=1070 \text{ Hz}$

7 0

3 years ago

The equation of a progressive

Juliette [100K]

Answer:

Amplitude = 0.02m

Frequency = 640 Hz

Wavelength, λ = 0.5m

v = 320 m/s

Explanation:

Given the wave equation :

y=0.02 sin2π/0.5 (320t - x) where x and y are in

meters and t is in second

Comparing the above relation with the general wave equation :

y(x, t) = Asin2π/λ(wt - kx)

The amplitude, A = 0.02

From the equation :

2π/0.5 = 2π/λ

λ = 0.5 m

320t = vt

Hence, v = 320 m/s

Recall :

v = fλ

320 = f * 0.5

f = 320 / 0.5

f = 640 Hz

6 0

3 years ago

A model rocket blasts off from the ground, rising straight upward with a constant acceleration that has a magnitude of 85.0 m/s2

sergey [27]

Answer:

Maximum height attained by the model rocket is 2172.87 m

Explanation:

Given,

Initial speed of the model rocket = u = 0
acceleration of the model rocket = $a\ =\ 85.0 m/s^2$
time during the acceleration = t = 2.30 s

We have to consider the whole motion into two parts

In first part the rocket is moving with an acceleration of a = 85.0 $m/s^2$ for the time t = 2.30 s before the fuel abruptly runs out.

Let $s_1$ be the height attained by the rocket during this time intervel,

$s_1\ =\ ut\ +\ \dfrac{1}{2}at^2\\\Rightarrow s_1\ =\ 0\ +\ 0.5\times 85\times 2.30^2\\\Rightarrow s_1\ =\ 224.825\ m$

And Final velocity at that point be v

$\therefore v\ =\ u\ +\ at\\\Rightarrow v\ =\ 0\ +\ 85.0\times 2.3\\\Rightarrow v\ =\ 195.5\ m/s.$

Now, in second part, after reaching the altitude of 224.825 m the fuel abruptly runs out. Therefore rocket is moving upward under the effect of gravitational acceleration,

Let ' $s_2$ ' be the altitude attained by the rocket to reach at the maximum point after the rocket's fuel runs out,

At that insitant,

initial velocity of the rocket = v = 195.5 m/s.

a = $-g\ =\ -9.81\ m/s^2$
Final velocity of the rocket at the maximum altitude = $v_f\ =\ 0$

From the kinematics,

$v^2\ =\ u^2\ +\ 2as\\\Rightarrow 0\ =\ u^2\ -\ 2gs_2\\\Rightarrow s_2\ =\ \dfrac{u^2}{2g}\\\Rightarrow s_2\ =\ \dfrac{195.5^2}{2\times 9.81}\\\Rightarrow s_2\ =\ 1948.02\ m$

Hence the maximum altitude attained by the rocket from the ground is

$s\ =\ s_1\ +\ s_2\ =\ 224.85\ +\ 1948.02\ =\ 2172.87\ m$

6 0

3 years ago

Question 5 (1 point)

Tom [10]

Answer: 18000 coulombs

Explanation:

Given that:

Current, I = 5.0A

Electric charge Q = ?

Time, T = 1 hour

(The SI unit of time is seconds. So, covert 1.0 hour to seconds)

If 1 hour = 60 minutes and 60 seconds = 1 minute

Then, 1.0 hour = (60 x 60)

= 3600 seconds

Since electric charge, Q = current x time

i.e Q = I x T

Q = 5.0 A x 3600 seconds

Q = 18000 coulombs

Thus, 18000 coulombs of charge flows through the lamp in this time.

4 0

3 years ago