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professor190 [17]
3 years ago
7

A 49.0-kg body is moving in the direction of the positive x axis with a speed of 268 m/s when, owing to an internal explosion, i

t breaks into three pieces. One part, whose mass is 9.5 kg, moves away from the point of explosion with a speed of 466 m/s along the positive y axis. A second fragment, whose mass is 5.0 kg, moves away from the point of explosion with a speed of 440 m/s along the negative x axis. What is the speed of the third fragment? Ignore effects due to gravity.
Physics
1 answer:
posledela3 years ago
6 0
The answer is 450. M/s
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Kinetic energy is movement, thus movement would be a characteristic that allows an object to have kinetic energy
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The dimensions of the disk of our milky way galaxy are:.
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Answer:

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2 years ago
An unstable atomic nucleus has a mass of 17.010-27kg, and starts out at rest. When it decays, it the original nucleus disintegra
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Answer:

Part a)

v = -(8.33\hat j + 9.33\hat i)\times 10^6 m/s

Part b)

E = 4.4 \times 10^{-13} J

Explanation:

As per momentum conservation we know that there is no external force on this system so initial and final momentum must be same

So we will have

m_1v_1 + m_2v_2 + m_3v_3 = 0

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(30\hat j + 33.6\hat i)\times 10^6 + 3.6 v = 0

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Part b)

By equation of kinetic energy we have

E = \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2 + \frac{1}{2}m_3v_3^2

E = \frac{1}{2}(5 \times 10^{-27})(6\times 10^6)^2 + \frac{1}{2}(8.4 \times 10^{-27})(4 \times 10^6)^2 + \frac{1}{2}(3.6 \times 10^{-27})(8.33^2 + 9.33^2) \times 10^{12}

E = 9\times 10^{-14} + 6.72 \times 10^{-14} + 2.82\times 10^{-13}

E = 4.4 \times 10^{-13} J

8 0
3 years ago
It takes 52,000 Joules to heat a cup of coffee to boiling from room temperature. How long a piece of 20 cm wide Aluminum foil wo
vovikov84 [41]

Answer:

L = 1.11 x 10^{6} m, is the length of piece of 20 cm wide Aluminum foil to make capacitor large enough to hold 52000 J of energy.

Explanation:

Solution:

Data Given:

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Dielectric Constant of the plastic Bag = 3.7 = K

Thickness = 2.6 x 10^{5} m =d

V = 610 volts

A = width x Length

width = 20 cm = 20 x 10^{-2} m

Length = ?

So,

we know that,

U = 1/2 C Δv^{2}

U = 52000 J

C = ?

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So,

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C = 0.28 F

And we also know that,

C = \frac{K*E*A}{d}

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Plugging in the values into the formula, we get:

0.28 = \frac{3.7 * 8.85 .10^{-12} * (0.20 . L) }{2.6 . 10^{5} }

Solving for L, we get:

L = 1.11 x 10^{6} m,

is the length of piece of 20 cm wide Aluminum foil to make capacitor large enough to hold 52000 J of energy.  

7 0
3 years ago
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What is the weight of a 4.2 kg bowling ball on Mars?

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Hope this helps

--Jay

8 0
3 years ago
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