A 49.0-kg body is moving in the direction of the positive x axis with a speed of 268 m/s when, owing to an internal explosion, i
t breaks into three pieces. One part, whose mass is 9.5 kg, moves away from the point of explosion with a speed of 466 m/s along the positive y axis. A second fragment, whose mass is 5.0 kg, moves away from the point of explosion with a speed of 440 m/s along the negative x axis. What is the speed of the third fragment? Ignore effects due to gravity.
1 answer:
You might be interested in
Answer:
here given is a weight
then force becomes mg
that is F=Mg
=4*9.8
then by using the formula
F=Ma
a=F/M
=4*9.8/9.8
=4
Explanation:
Answer:
a. 60 N*s
b. 60 (kg*m)/s
c. 3 m/s
Explanation:
Givens:
m = 20 kg
v_i = 0 m/s
t = 10 s
F = 6 N
a) Impulse:
I = F*t
I = 6 N*10 s
I = 60 N*s
b) Momentum:
p = v*m
F = m(a)
a = F/m
a = 6 N/20 kg
a = 0.3m/s^2
a = (v_f -v_i)/t
v_f = (0.3 m/s^2)*10 s
v_f = 3.0 m/s
p = 3 m/s*20 kg
p = 60 (kg*m)/s
c. Final velocity
a = (v_f -v_i)/t
v_f = (0.3 m/s^2)*10 s
v_f = 3.0 m/s
Answer:
a) The speed is 61.42 m/s
b) The drag force is 10.32 N
Explanation:
a) The Reynold´s number for the model and prototype is:
Equaling both Reynold's number:
Clearing Vm:
b) The drag force is:
Explanation:
t = usin©/g
Where t is the time to reach the maximum height
Time spent in air is T = 2t
Hence, T = 2usin©/g
T = 2 x 20 x sin 65°/ 9.8
T = 3.69s
Power = (current) x (voltage) .
