Answer:
2.4 m/s
Explanation:
Momentum is conserved.
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
(0.08 kg)(0.5 m/s) + (0.05 kg)(0 m/s) = (0.08 kg)(-0.1 m/s) + (0.05 kg) v
0.04 kg m/s = -0.08 kg m/s + (0.05 kg) v
0.12 kg m/s = (0.05 kg) v
v = 2.4 m/s
A reasonable estimate for the height of the walls in an ordinary American home is 2.5m.
<h3>What is wall estimation?</h3>
Building gauge is of two sorts one is known as Rough Cost Estimate. This gauge won't depict the specific expense of the structure, however it can provide you with the rough expense worth of the structure that will help adequately in overseeing cash for the structure. Harsh Cost Estimate is directed in various ways for various sort of structures. The rough complete wall length is found in running meters in this framework and this all out length accumulated by the rate per running meter of the wall gives an actually solid cost. Assessment hypothesis is a part of insights that arrangements with assessing the upsides of boundaries in light of estimated experimental information that has an irregular part. The boundaries depict a fundamental actual setting so that their worth influences the circulation of the deliberate information.
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To determine the displacement, since we are given the potential energy, we use the equation for potential energy. For a spring, it is one-half the product of the spring constant and the square of the displacement. We do as follows:
PE = kx^2/2
5 Nm = 50N/m (x^2)
x = 0.32 m
Therefore, the displacement would be 0.32 m.
This question involves the concepts of equilibrium and Newton's third law of motion.
The support force will be "1 pound" for the empty bucket and the support force will be "6 pounds" after pouring water into it.
- According to the condition of equilibrium, the sum of forces acting on a stationary object must be zero. Hence, the support force of the table will be equal to the total mass of the bucket.
- According to Newton's Third Law of Motion every action force has an equal but opposite reaction force. Hence, the support force will be a reaction force to the weight of the bucket.
Therefore, the support force in each case will be equal to the total mass of the bucket:
Case 1 (empty bucket):
<u>support force = 1 pound</u>
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Case 1 (water poured):
support force = 1 pound + 5 pound
<u>support force = 6 pound</u>
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