Answer:
Electric Field = E = 36.848 N/C
Explanation:
In accordance with Columb's law
E = k Q1 Q2 / r.r = 8.99 x 10^9 x 5.0 x 10^-6 x 5.8 x 10^-6 / 0.084 x 0.084
= 36948.6961 x 10^-3 = 36.848 N/C
A.) is chemical, B.) is physical, C.) is physical, D.) is chemical, E.) is physical, F.) is physical, G.) is physical, and H.) is chemical.
<span> The boiling point of water at sea level is 100 °C. At higher altitudes, the boiling point of water will be.....
a) higher, because the altitude is greater.
b) lower, because temperatures are lower.
c) the same, because water always boils at 100 °C.
d) higher, because there are fewer water molecules in the air.
==> e) lower, because the atmospheric pressure is lower.
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Water boils at a lower temperature on top of a mountain because there is less air pressure on the molecules.
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I hope this is helpful. </span>
Answer: velocity
Explanation: it's the rate of change of the objects position/ consistent change
Complete Question
The complete question is shown on the first uploaded image
Answer:
a
![\theta_{max} =18.38^o](https://tex.z-dn.net/?f=%5Ctheta_%7Bmax%7D%20%3D18.38%5Eo)
b
New ![n_{cladding} =1.491](https://tex.z-dn.net/?f=n_%7Bcladding%7D%20%3D1.491)
Explanation:
From the question we are told that
The refractive index of the core is ![n_{core} = 1.497](https://tex.z-dn.net/?f=n_%7Bcore%7D%20%3D%201.497)
The refractive index of the cladding is ![n_{cladding} = 1.421](https://tex.z-dn.net/?f=n_%7Bcladding%7D%20%3D%201.421)
Generally according to Snell's law
![n_{core} * sin(90- \theta) = n_{cladding} * sin (90)](https://tex.z-dn.net/?f=n_%7Bcore%7D%20%2A%20sin%2890-%20%5Ctheta%29%20%3D%20n_%7Bcladding%7D%20%2A%20sin%20%2890%29)
Where
is the largest angle a largest angle a ray will make with respect to the interface of the fiber and experience total internal reflection
![\theta_{max} = 90 - sin^{-1} [\frac{n_{cladding}}{n_{core}} ]](https://tex.z-dn.net/?f=%5Ctheta_%7Bmax%7D%20%3D%2090%20-%20sin%5E%7B-1%7D%20%5B%5Cfrac%7Bn_%7Bcladding%7D%7D%7Bn_%7Bcore%7D%7D%20%5D)
![\theta_{max} = 90 - sin^{-1} [\frac{1.421}{1.497}} ]](https://tex.z-dn.net/?f=%5Ctheta_%7Bmax%7D%20%3D%2090%20-%20sin%5E%7B-1%7D%20%5B%5Cfrac%7B1.421%7D%7B1.497%7D%7D%20%5D)
![\theta_{max} =18.38^o](https://tex.z-dn.net/?f=%5Ctheta_%7Bmax%7D%20%3D18.38%5Eo)
Given from the question the the largest angle is 5°
Generally the refraction index of the cladding is mathematically represented as
![n_{cladding} = n_{core} * sin (90 - 5)](https://tex.z-dn.net/?f=n_%7Bcladding%7D%20%3D%20n_%7Bcore%7D%20%2A%20sin%20%2890%20-%205%29)
![n_{cladding} =1.491](https://tex.z-dn.net/?f=n_%7Bcladding%7D%20%3D1.491)