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mihalych1998 [28]
3 years ago
10

Write equations for the horizontal and vertical lines passing through the point (-6,1)

Mathematics
1 answer:
Oksanka [162]3 years ago
4 0

Answer:

y = 1 and x = - 6

Step-by-step explanation:

The equation of a horizontal line parallel to the x- axis is

y = c ( where c is the value of the y- coordinates the line passes through )

The line passes through (- 6, 1 ) with y- coordinate 1 , then

y = 1 ← equation of horizontal line

The equation of a vertical line parallel to the y- axis is

x = c ( where c is the value of the x- coordinates the line passes through )

The line passes through (- 6, 1 ) with x- coordinate - 6 , then

x = - 6  ← is equation of vertical line

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34
Vadim26 [7]

Answer:

They are similar by the definition of similarity in terms of a dilation

Step-by-step explanation:

The given vertices of triangle ΔABC are;

A(1, 5), B(3, 9), and C(5, 3)

The vertices of triangle ΔDEF are;

D(-3, 3), E(-2, 5), and F(-1, 2)

Therefore, we get;

The length of segment, \overline{AB} = √((9 - 5)² + (3 - 1)²) = 2·√5

The length of segment, \overline{BC} = √((9 - 3)² + (3 - 5)²) = 2·√10

The length of segment, \overline{AC} = √((5 - 3)² + (1 - 5)²) = 2·√5

The length of segment, \overline{DE} = √((5 - 3)² + (-2 - (-3))²) = √5

The length of segment, \overline{EF} = √((2 - 5)² + (-1 - (-2))²) = √10

The length of segment, \overline{DF} = √((2 - 3)² + (-1 - (-3))²) = √5

∴ \overline{AB}/\overline{DE} = 2·√5/(√5) = 2

\overline{BC}/\overline{EF} = 2·√10/(√10) = 2

\overline{AC}/\overline{DF} = 2·√5/(√5) = 2

The ratio of their corresponding sides are equal and therefore;

ΔABC and ΔDEF are similar by the definition of similarity in terms of dilation.

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Step-by-step explanation:

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