Answer:
36 and 54
Step-by-step explanation:
54-36=18
54+36= 90
Answer:
a y=25+89x b 25 c 14
Step-by-step explanation:
89*22=1958
1983-1958=25(service fee)
(1271-25)/89=14
Dilation by a scale factor of 1/2 followed by a translation of 1.5 units down.
<h3>What is dilation?</h3>
Dilation is a transformation, which is used to resize the object. Dilation is used to make the objects larger or smaller.
Here, △ HIJ are:
IH = 3
IJ = 4
then using the scale factor = 1/2 we get
Therefore, we have:
I'H '= 1.5
I'J '= 2
Hence, dilation by a scale factor of 1/2 followed by a translation of 1.5 units down.
Learn more about this concept here:
brainly.com/question/1011146
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I'll go by boxes (top statement box is #1, top reason box is #2, etc.)
If you don't have enough boxes, you can omit (remove) the first 2 I wrote, which is the given
1. 8y = 9x - 14; y = 5
2. Given
3. 8(5) = 9x - 14
4. Substitution
5. 40 = 9x - 14
6. Simplification (or multiplication)
7. 54 = 9x
8. Additive property of equality
9. 6 = x
10. Division property of equality
11. x = 6
12. Symmetrical property of equality
Hope this helps (:
Hello!
Here are some rules to determine the number of significant figures.
- Numbers that are not zero are significant (45 - all are sigfigs)
- Zeros between non-zero digits are significant (3006 → all are sigfigs)
- Trailing zeros are not significant (0.067 → the first two zeros are not sigfigs)
- Trailing zeros after a decimal point are always significant (1.000 → all are sigfigs)
- Trailing zeros in a whole number are not significant (7800 → the last two zeros are not sigfigs)
- In scientific notation, the exponential digits are not significant, known as place holders (6.02 x 10² → 10² is not a sigfig)
Now, let's find the number of significant figures in each given number.
A). 296.54
Since these digits are all <em>non-zero</em>, there are 5 significant figures.
B). 5003.1
Since the two <em>zeros are between non-zero digits</em>, they are significant figures. Thus, there are 5 significant figures.
C). 360.01
Again, the two zeros are between non-zero digits. There are 5 significant figures.
D). 18.3
All of these digits are non-zero, hence, there are 3 significant figures.
Therefore, expression D has the fewest number of significant figures being 3.
