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Goshia [24]
3 years ago
12

Hi..Please answer questions???​

Physics
1 answer:
Nadya [2.5K]3 years ago
3 0

Answer:

A

Explanation:

Becuse its complete number

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Please !!! I really need help !!! How do I understand these ?!!!!
trasher [3.6K]

Answer

The answer for the first one I think is false.

The second one would be true i think. I hope i got it right and have a wonderful day

8 0
3 years ago
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At what distance will the weight of a body be halved , Earth's radius=6.4×10^6
Sholpan [36]

A body of mass m has weight

F = GMm/r²

on the surface of the Earth, where G is the universal gravitational constant, M is the mass of the Earth, and r is it's radius.

If the weight is to be halved, then we have

1/2 F = 1/2 GMm/r² = (1/√2)² GMm/r² = GMm/(√2 r²)

so the distance between the body and the planet's center needs to be

√2 × 6.4 × 10⁶ m ≈ 9.1 × 10⁶ m

5 0
3 years ago
Making quick glances to the roadway in front of your vehicle is called?
umka2103 [35]

Answer:

safety check.

Explanation:

5 0
3 years ago
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If a set of Bluetooth headphones has a resistance of 4.5 ohms and has a current of 1.5 amps, what is the voltage of the headphon
FinnZ [79.3K]

Answer:

6.75 v

Explanation:

7 0
3 years ago
Very lost please help.
V125BC [204]
A) The acceleration is due to gravity at any given point if you look at it vertically, so -10 m/s^2.

b) sin(25) = V_y/V, so V_y = V*sin(25). We use V = V_0 + a t and then the final speed must be 0 because it stops at the highest point. So 0 = V_y - 10t. Solve for t and you get t = 32sin(25)/10 = 16sin(25)/5

c) Y = Y_0 + V_0t + (1/2)at^2, and then we plug the values: Y_m_a_x = 32sin(25)*t - (1/2)*10*t^2 and we already have the time from "b)", so Y_m_a_x = [(32sin(25))*(32sin(25)/10)] - 5(32sin(25)/10)^2; then we just rearrange it Y_m_a_x = 10[(32sin(25))^2/100] - 5 [(32sin(25))^2/100] and finally Y_m_a_x = 5[(32sin(25))^2/100] = (32sin(25))^2/20
6 0
3 years ago
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