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vampirchik [111]
3 years ago
13

The driver of a 1,000 kg car travelling at a speed of 16.7 m/s applies the car's brakes when he sees a red light. the car's brak

es provide a frictional force of 8,000 n. determine the stopping distance of the car.
Physics
2 answers:
Dmitry [639]3 years ago
6 0
Energy conservation : 
<span>kinetic energy Ek = braking work W </span>
<span>mV^2 = 2Fb*x </span>
<span>x = mV^2/2Fb = 1000*16.7^2/16.000 = 17.43 meters</span>
Sauron [17]3 years ago
5 0

Answer:

1.04 meters

Explanation:

Thinking process:

Gathering the data

mass  = 1 000 kg

speed, u = 16.7 m/s

Frictional force = 8 000 N

distance, s  = ?

final velocity  = 0 (car stops)

We know that the final velocity is calculated as: v^{2} = u^{2}  + 2as

But, a = negative (declaration)

And F = ma

      8 000 = 1000 (a)\\          a = -8 m^{-2}

substituting, 0 = (16.7) - 2 (8) (s)

                    -16.7 = -16s

                         s  = 1.04 m

   Stopping distance = 1.04 meters

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