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Mariulka [41]
3 years ago
8

True or false earth orbit is nearly circular

Physics
2 answers:
Simora [160]3 years ago
4 0
The answer would be true
Naddik [55]3 years ago
4 0
I guess that depends on what you mean by "nearly".
"Nearly" is one of those rubber words that means different things
to different people, and may even mean different things to the same
person at different times and in different situations.

I can tell you this much:

-- The Earth's orbit is an ellipse with eccentricity of  0.0167... .

-- At closest approach to the sun (perihelion, around January 3), the Earth
is about  3.3% closer to the sun than at its farthest (aphelion, around July 5).

-- When the true shape of the orbit is drawn on paper, its departure from
a perfect circle is not noticeable.

So to me, Earth's orbit is "nearly circular".  Your interpretation of the same
words may be different.
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Answer:

It assembles the messages in a way that has meaning for us, and can store that information in our memory. The brain controls our thoughts, memory and speech, movement of the arms and legs, and the function of many organs within our body. The central nervous system (CNS) is composed of the brain and spinal cord.Explanation:

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A plane startling from rest accelerates at 3 m/s Square. Calculate the increase in velocity after 25 sec
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Answer:

75 m/s

Explanation:

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V = U + a * t

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After  25 seconds , subjected to the given acceleration velocity is increased from 0 to 75 m/s

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3 years ago
A hot iron horseshoe (mass = 0.35 kg ), just forged, is dropped into 1.40 L of water in a 0.45 kg iron pot initially at 22.0°C.
olga_2 [115]

Answer:

420 °C

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m_{w} = mass of the water = 1.40 L = 1.40 kg

m_{i} = mass of the iron pot = 0.45 kg

c_{i} = specific heat of iron = 450 J kg⁻¹ °C⁻¹

c_{w} = specific heat of water = 4186 J kg⁻¹ °C⁻¹

T_{hi} = initial temperature of the horseshoe = ?

T_{wi} = initial temperature of the water = 22 °C

T_{pi} = initial temperature of the iron pot = 22 °C

T_{f} = final temperature = 32 °C

Using conservation of Heat

m_{h}c_{i}(T_{hi} - T_{f}) = m_{w}c_{w}(T_{f} - T_{wi}) + m_{i}c_{i}(T_{f} - T_{pi})

(0.35)(450)(T_{hi} - 32) = (1.40)(4186)(32 - 22) + (0.45)(450)(32 - 22)

(157.5)(T_{hi} - 32) = 60629

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T_{hi} = 420 °C

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3 years ago
Differences between concave and convex meniscus​
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