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Ann [662]
4 years ago
14

I need an answer ASAP .....

Physics
2 answers:
katen-ka-za [31]4 years ago
5 0
Total internal reflection is a powerful tool since it can be used to confine light. ... If light is incident on a cable end with an angle of incidence greater than the critical angle then the light will remain trapped inside the glass strand.
Harrizon [31]4 years ago
4 0

Answer:

Hope this helped :

Explanation:

When light passes from a medium with one index of refraction (m1) to another medium with a lower index of refraction (m2), it bends or refracts away from an imaginary line perpendicular to the surface (normal line). As the angle of the beam through m1 becomes greater with respect to the normal line, the refracted light through m2 bends further away from the line.

At one particular angle (critical angle), the refracted light will not go into m2, but instead will travel along the surface between the two media (sine [critical angle] = n2/n1 where n1 and n2 are the indices of refraction [n1 is greater than n2]). If the beam through m1 is greater than the critical angle, then the refracted beam will be reflected entirely back into m1 (total internal reflection), even though m2 may be transparent!

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A machine applies a force of 100 newtons over a distance of 10 meters to raise a 500 newton
kiruha [24]

Explanation:

work input is the work done by the machine in lifting the drum = Force × distance

100N × 10m

= 1000 J

5 0
3 years ago
The talk test can be used to measure the __________. A. knowledge of an activity B. intensity of an activity C. length of an act
aivan3 [116]
I would say A or B if there’s a text can u post that as well but I’m just going by what it sound like
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3 years ago
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This boy uses a force to lift a heavy rock. (He is carrying it.) What can the boy do if he wants to lift the same rock more quic
lutik1710 [3]
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3 years ago
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The landing of a spacecraft is cushioned with the help of airbags. During its landing on Mars, the velocity of downward fall is
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3 years ago
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Se lanza un cohete en un ángulo de 53° sobre la horizontal con una rapidez inicial de 100 m/s. El cohete se mueve por
likoan [24]

Answer:

Explanation:

v = u + at

v₃ = 100 +30.0(3.00) = 190 m/s

s = vt + ½at²

y₃ = (100sin53)(3.00) + ½(30sin53)(3.00²) = 347.4 m

x₃ = (100cos53)(3.00) + ½(30cos53)(3.00²) = 261.8 m

a) v² = u² + uas  

s = (v² - u²) / 2a

ymax = 347.4 + (0² - (190sin53)²) / (2(-9.80)) = 1,522 m

b) t₁ = 3.00 s

   t₂ = (190sin53) / 9.80 = 15.5 s

   t₃ = √(2(1522) / 9.80) = 17.6 s

t = 3.00 + 15.5 + 17.6 = 36.1 s

c) xmax = 261.8 + (190cos53)( 15.5 + 17.6) = 4,047 m

3 0
3 years ago
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