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Alinara [238K]
2 years ago
5

Cann someone please help??

Mathematics
2 answers:
Aleks [24]2 years ago
6 0

Answer:

It can be simplified to 5√2

Step-by-step explanation:

vazorg [7]2 years ago
3 0

option 1 is correct [5root2]

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The number of gallons of water in a large tank at time (t) minutes is given by the function W(t)=160,000-8,000t+t². Find the ave
sergij07 [2.7K]

The number of gallons of water in the tank at t=10 is

... W(10) = 160,000 -10(8000 -10) = 80100

The number of gallons of water in the tank at t=10.5 is

... W(10.5) = 160,000 -10.5(8000 -10.5) = 76110.25

The rate of change over the interval is

... (W(10.5) - W(10))/(10.5 - 10) = (76110.25 - 80100)/(0.5) = -7979.5

The average rate of change in the number of gallons of water in the tank over the interval is -7979.5 gal/min.

The sign is negative, so the amount of water is decreasing.

3 0
3 years ago
10 (w-4)=4 (w+4)+4w​
eimsori [14]

Answer:

w = 28

Step-by-step explanation:

10(w-4) = 4(w+4)+4w

1. distribute

10w - 40 = 4w +16 +4w

2. collect like terms

10w -4w - 4w = 40 +16

3. solve

2w = 56

w = 28

:D

8 0
3 years ago
Obtain the general solution to the equation. (x^2+10) + xy = 4x=0 The general solution is y(x) = ignoring lost solutions, if any
alukav5142 [94]

Answer:

y(x)=4+\frac{C}{\sqrt{x^2+10}}

Step-by-step explanation:

We are given that a differential equation

(x^2+10)y'+xy-4x=0

We have to find the general solution of given differential equation

y'+\frac{x}{x^2+10}y-\frac{4x}{x^2+10}=0

y'+\frac{x}{x^2+10}y=4\frac{x}{x^2+10}

Compare with

y'+P(x) y=Q(x)

We get

P(x)=\frac{x}{x^2+10}

Q(x)=\frac{4x}{x^2+10}

I.F=e^{\int\frac{x}{x^2+10} dx}=e^{\frac{1}{2}ln(x^2+10)}

e^{ln\sqrt(x^2+10)}=\sqrt{x^2+10}

y\cdot \sqrt{x^2+10}=\int \frac{4x}{x^2+10}\times \sqrt{x^2+10} dx+C

y\cdot \sqrt{x^2+10}=\int \frac{4x}{\sqrt{x^2+10}}+C

y\cdot \sqrt{x^2+10}=4\sqrt{x^2+10}+C

y(x)=4+\frac{C}{\sqrt{x^2+10}}

6 0
3 years ago
-0.5,1.25,-1/3,0.5,-5/3 ordered from least to greatest
vampirchik [111]

Answer:

Step-by-step explanation:

-5/3,-0.5,-1/3,0.5,1.25

8 0
2 years ago
I need help on this question
Ilia_Sergeevich [38]
I think the answer is 16
3 0
3 years ago
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