The number of gallons of water in the tank at t=10 is
... W(10) = 160,000 -10(8000 -10) = 80100
The number of gallons of water in the tank at t=10.5 is
... W(10.5) = 160,000 -10.5(8000 -10.5) = 76110.25
The rate of change over the interval is
... (W(10.5) - W(10))/(10.5 - 10) = (76110.25 - 80100)/(0.5) = -7979.5
The average rate of change in the number of gallons of water in the tank over the interval is -7979.5 gal/min.
The sign is negative, so the amount of water is decreasing.
Answer:

Step-by-step explanation:

1. distribute

2. collect like terms

3. solve


:D
Answer:

Step-by-step explanation:
We are given that a differential equation

We have to find the general solution of given differential equation


Compare with

We get


I.F=





Answer:
Step-by-step explanation:
-5/3,-0.5,-1/3,0.5,1.25